Question : If a + b + c = 1, ab + bc + ca = –1, and abc = –1, then what is the value of a3 + b3 + c3?
Option 1: 1
Option 2: 5
Option 3: 3
Option 4: 2
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Correct Answer: 1
Solution : a3 + b3 + c3 = (a + b + c)(a2 + b2 + c2 – ab – bc – ac) + 3abc = (a + b + c)((a + b + c)2 – 3ab – 3bc – 3ac) + 3abc = (1){12 –3(–1)} + 3(–1) = 1 Hence, the correct answer is 1.
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Question : If a + b + c = 0, then the value of (a + b – c)2 + ( b + c – a)2 + ( c + a – b)2 is:
Option 1: 0
Option 2: 8abc
Option 3: 4(a2 + b2 + c2)
Option 4: 4(ab + bc + ca)
Question : If a + b + c = 19, ab + bc + ca = 120, then what is the value of a3 + b3 + c3 – 3abc?
Option 1: 18
Option 2: 23
Option 3: 31
Option 4: 19
Question : If (a + b + c) = 7 and ab + bc + ca = 12, find the value of a2 + b2 + c2.
Option 1: 29
Option 2: 31
Option 3: 27
Option 4: 25
Question : If A + B = – 5 and AB = 6, then find the value of A3 + B3.
Option 1: 35
Option 2: 45
Option 3: –35
Option 4: 215
Question : If a + b + c = 15 and a2 + b2 + c2 = 83 then the value of a3 + b3 + c3 – 3abc:
Option 1: 200
Option 2: 180
Option 3: 190
Option 4: 210
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