Hello aspirant

The student who got 97.56 percentile will have his all India rank around 108,104.844

His Jee main score is good enough . He has qualified Jee main now a he should prepare for Jee advanced which is to be commenced on 23rd August. Admission to  IIT College will depend on J his  Jee Advanced score  . He can get good nit Institute.. But I think he should go for jee advanced.

Talking about computer science branch , there is tough competition. If he really needs CS branch then he should try in nit

Below are NIT COLLEGES

SARDAR VALLABH BAI PATEL NIT, SURAT

NIT, TIRUCHIRAPPALLI

MOTILAL NEHRU NIT, ALLAHABAD

FR. AMBEDKAR NIT , JALANDHAR

NIT KARNATAKA, SURATHKAL

TOP IIT COLLEGES IN INDIA

IIT BOMBAY

IIT MADRAS

IIT DELHI

IIT KANPUR

IIT KHARAGPUR

Wait for the results of Jee main session 2 and then for college prediction following link may help

https://engineering.careers360.com/jee-main-college-predictor

Hello there,
According to the rank formula,[100-97.56*869010/100], the student's rank is 21203 approximately, and he is from the general category. So, here's a list of colleges where he can apply for computer science:
1. NIT Agartala
2. NIT Goa
3. NIT Puducherry
4. NIT Mizoram
5. IIIT Guwahati
6. IIIT Kota
These are few colleges where you can apply. You can apply in all NITs with your rank.
Here's a link where you can check out the cut-off ranks of different NITs:
https://engineering.careers360.com/articles/nits-cutoff-for-b-tech-computer-science-and-engineering
Hope this answer helps you.
Good luck!!

Hello Aspirant,

With your score you can apply for all the NITs. However in top NITs it can be a bit difficult to get Computer Science as it is the most preferred branch. However you do have chances of getting Computer Science in the top NITs.

https://www.google.com/amp/s/engineering.careers360.com/articles/nits-cutoff-for-b-tech-computer-science-and-engineering/amp

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