Question : If $xy=48$ and $x^2+y^2=100$, then $(x+y)$ is:
Option 1: 12
Option 2: 16
Option 3: 18
Option 4: 14
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Correct Answer: 14
Solution : Given: $xy = 48$ and $x^{2}+y^{2} = 100$ We know the algebraic identity, $(x+y)^{2} = x^{2}+y^{2}+2xy$ By substituting the values in the above equation, we get: $⇒(x+y)^{2} = 100+2×48$ $⇒(x+y) = \sqrt{196}$ $\therefore (x+y) = 14$ Hence, the correct answer is 14.
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Question : If $\small x+y+z=6$ and $xy+yz+zx=10$, then the value of $x^{3}+y^{3}+z^{3}-3xyz$ is:
Option 1: 36
Option 2: 48
Option 3: 42
Option 4: 40
Question : If $x+y=4, x^{2}+y^{2}=14$ and $x>y$, then the correct value of $x$ and $y$ is:
Option 1: $2+\sqrt{3} \text{ and } 2-\sqrt{3}$
Option 2: $2-\sqrt{2} \text{ and } \sqrt{3}$
Option 3: $3 \text{ and } 1$
Option 4: $2+\sqrt{3} \text{ and } 2\sqrt{2}$
Question : If $x^2+\frac{1}{x^2}=4$, then what is the value of $x^4+\frac{1}{x^4}$?
Option 1: 16
Option 2: 14
Option 3: 12
Option 4: 20
Question : If 8% of $x$ = 4% of $y$, then 20% of $x$ is:
Option 1: 10% of $y$
Option 2: 16% of $y$
Option 3: 40% of $y$
Option 4: 80% of $y$
Question : If $x+y+z=13$ and $x^2+y^2+z^2=69$, then $xy+z(x+y)$ is equal to:
Option 1: 70
Option 2: 40
Option 3: 50
Option 4: 60
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