New
Question : If $3 x=\sec A$ and $\frac{3}{x}=\tan A$, then $9\left(x^2-\frac{1}{x^2}\right)$ is:
Option 1: $3$
Option 2: $9$
Option 3: $1$
Option 4: $\frac{1}{9}$
New: SSC CGL 2025 Tier-1 Result
Latest: SSC CGL complete guide
Suggested: Month-wise Current Affairs | Upcoming Government Exams
Correct Answer: $1$
Solution : We know that, $\sec ^2A-\tan^2 A=1$ ⇒ $(3x)^2-(\frac{3}{x})^2=1$ ⇒ $9x^2-\frac{9}{x^2}=1$ ⇒ $9\left(x^2-\frac{1}{x^2}\right)=1$ Hence, the correct answer is $1$.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile