Question : If $9x^2+16y^2=60$ and $3x+4y=6$, then the value of $xy$ is:
Option 1: –1
Option 2: 1
Option 3: –2
Option 4: 2
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Correct Answer: –1
Solution : Given: $9x^2+16y^2=60$ and $3x+4y=6$ $3x+4y=6$ Squaring both sides of the above expression, we get, ⇒ $(3x+4y)^2=6^2$ ⇒ $9x^2+16y^2+24xy=36$ Substitute the value of $9x^2+16y^2=60$ in the above expression, we get, $60+24xy=36$ ⇒ $24xy=36-60$ ⇒ $24xy=–24$ ⇒ $xy=–1$ Hence, the correct answer is –1.
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Question : If $ax–4y = – 6$ has a slope of $-\frac{3}{2}$, what is the value of $a$?
Option 1: 6
Option 2: 3
Option 3: – 6
Option 4: – 3
Question : If $(x-\frac{1}{3x})=\frac{1}{3}$, then the value of $3(x-\frac{1}{3x})$ is:
Option 2: –2
Option 3: 1
Question : What is the equation of the line whose y-intercept is $-\frac{3}{4}$ and making an angle of $45^{\circ}$ with the positive x-axis?
Option 1: $4x–4y=3$
Option 2: $4x-4y=–3$
Option 3: $3x–3y=4$
Option 4: $3x–3y=–4$
Question : If $xy = -6$ and $x^3+ y^3= 19$ ($x$ and $y$ are integers), then what is the value of $\frac{1}{x^{–1}}+\frac{1}{y^{–1}}$?
Question : If $\frac {x^2+3x+1}{x^2–3x+1}=\frac{1}{2 }$, then the value of $(x+\frac{1}{x})$ is:
Option 1: 9
Option 2: –9
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