Question : If $\tan \theta+\sin \theta=A$ and $\tan \theta-\sin \theta=B$, then what is the value of $A^2-B^2$?
Option 1: $\tan \theta \sin \theta$
Option 2: $4 \cot \theta$
Option 3: $4 \tan \theta \sin \theta$
Option 4: $2 \tan \theta \sin \theta$
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Correct Answer: $4 \tan \theta \sin \theta$
Solution : $\tan \theta+\sin \theta=A$ and $\tan \theta-\sin \theta=B$ $ A^2-B^2=(A+B)(A-B) $ $⇒ A^2 - B^2 = (2 \tan \theta) × (2 \sin \theta)$ $⇒ A^2 - B^2 = 4 \tan \theta \sin \theta $ Therefore, $A^2 - B^2 = 4 \tan \theta \sin \theta$ Hence, the correct answer is $4 \tan \theta \sin \theta$.
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Question : If $\theta$ be an acute angle and $\tan \theta+\cot \theta=2$, then the value of $2 \tan ^2 \theta+\cot ^2 \theta+\tan ^4 \theta \cot ^4 \theta$ is:
Option 1: 4
Option 2: 2
Option 3: 3
Option 4: 6
Question : The value of $\frac{\sin\theta-2\sin^{3}\theta}{2\cos^{3}\theta-\cos\theta}$ is equal to:
Option 1: $\sin\theta$
Option 2: $\cos\theta$
Option 3: $\tan\theta$
Option 4: $\cot\theta$
Question : If $\tan \theta-\cot \theta=4$, then find the value of $\tan ^2 \theta+\cot ^2 \theta$.
Option 1: 16
Option 2: 20
Option 3: 14
Option 4: 18
Question : If $\sqrt{3} \tan ^2 \theta-4 \tan \theta+\sqrt{3}=0$, then what is the value of $\tan ^2 \theta+\cot ^2 \theta$?
Option 1: $\frac{4}{3}$
Option 2: $\frac{10}{3}$
Option 3: $3$
Option 4: $\frac{6}{5}$
Question : If $\sin \theta-\cos \theta=0$, then what is the value of $\sin ^2 \theta+\tan ^2 \theta$ ?
Option 1: $\frac{1}{2}$
Option 2: $1$
Option 3: $\frac{4}{5}$
Option 4: $\frac{3}{2}$
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