Question : If $(4 x-7 y)=11$ and $x y=8$, what is the value of $16 x^2+49 y^2$, given that $x$ and $y$ are positive numbers?
Option 1: 596
Option 2: 484
Option 3: 569
Option 4: 448
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Correct Answer: 569
Solution : Given: $(4 x-7 y)=11$ and $x y=8$ Now, $(4 x-7 y)=11$ ⇒ $(4 x-7 y)^2=11^2$ [squaring both sides] ⇒ $16 x^2+49 y^2-56xy=121$ ⇒ $16 x^2+49 y^2-56(8)=121$ ⇒ $16 x^2+49 y^2=569$ Hence, the correct answer is 569.
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Question : If $4 x^2+y^2=40$ and $x y=6$, find the positive value of $2 x+y$.
Option 1: 8
Option 2: 6
Option 3: 5
Option 4: 4
Question : If $x$ and $y$ are positive numbers such that $x - y = 5$ and $xy = 150$, the value of $(x + y)$ is:
Option 1: 45
Option 2: 25
Option 3: 35
Option 4: 15
Question : If $(x-\frac{1}{3})^2+(y-4)^2=0$, then what is the value of $\frac{y+x}{y-x}$?
Option 1: $\frac{11}{13}$
Option 2: $\frac{13}{11}$
Option 3: $\frac{16}{9}$
Option 4: $\frac{9}{16}$
Question : If $x^{2}+y^{2}+z^{2}=14$ and $xy+yz+zx=11$, then the value of $(x+y+z)^{2}$ is:
Option 1: 16
Option 3: 36
Option 4: 49
Question : If $x-y=1$ and $x^2+y^2=41$ where $x, y \geq 0$, then the value of $x+y$ will be:
Option 1: 9
Option 2: 8
Option 3: 6
Option 4: 7
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