Thanks A2A @bharwalsakshi !
The chemical equation becomes:-
C2H4(g)+3O2(g)-----> 2CO2(g)+2H2O(l)
Del(H)={Summation of del Hf of products}-{Summation of del Hf of reactants}
={(2*-394)+(2*-286)}-(52+0)
=(-788-572)-52 = -1412 kJ/mol
Hope this helps!
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