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If I score 132 in jee main 2021, 25 february shift 2 then what will be my rank and percentile


devendramhasade8147 27th Feb, 2021
Answer (1)
ADITYA KUMAR Student Expert 27th Feb, 2021

Hi


It's quite difficult to make prediction but yes as per previous year trends, with 132 mark

  • your percentile will be around 98.3 percentile

  • your rank will be  around 15,000- 16,000 ,for this rank vs marks vs percentile you can refer to our page for which link is provided below:-

https://engineering.careers360.com/articles/jee-main-marks-vs-percentile/amp#referrer=https://www.google.com&csi=1

These above  rank / percentile are just estimated rank and percentile, the actual rank/ percentile will vary a bit as above prediction is on the basis of past year trends but rank /percentile  keeps changing every year depending upon various factors like  number of students that appeared in the exam, kind of marks obtained by them , toughness level of the examination for different shifts of the exam etc

Also,

You can predict your rank using rank predictor at

And yes, with 132 marks with above predicted rank , you have good chances to get a seat in NIT, for example you have chances in

  • NIT jamshedpur:-Electrical and Electronics Engineering

  • NIT sikkim:- computer science

And more

For this you can refer to our page for which link is provided below:-

https://engineering.careers360.com/articles/nits-cutoff-for-top-btech-branches

Above prediction of colleges is on the basis of past year data but  cut off/closing rank for colleges keeps changing every year depending upon many factors like number of students that appeared in the examination etc so

to have a personalised report on your chances of getting a college you can go through our college predictor, it will give you complete list of colleges which you can get on the basis of the category you belong to,  your home state, your gender etc, the link for  jee main college predictor is provided below

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

If you have any other doubt then you can always reach us to clear them :) we are always available to help you out and guide you



Thankyou



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