Question : If $\theta$ is an acute angle and $\sin \theta=\frac{21}{25}$, then what is the value of $\tan \theta$?
Option 1: $\frac{2 \sqrt{46}}{21}$
Option 2: $\frac{25}{2 \sqrt{46}}$
Option 3: $\frac{21}{2 \sqrt{46}}$
Option 4: $\frac{2 \sqrt{46}}{25}$
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Correct Answer: $\frac{21}{2 \sqrt{46}}$
Solution : Given, $\theta < 90°$ and $\sin \theta=\frac{21}{25}$ We know, $\sin\theta = \frac{\text{Perpendicular}}{\text{Hypotenuse}}$ ⇒ Perpendicular = 21 and Hypotenuse = 25 Using Pythagoras theorem, Hypotenuse2 = Perpendicular2 + Base2 ⇒ 252 = 212 + Base2 ⇒ Base = $\sqrt{25^2-21^2}$ ⇒ Base = $\sqrt{625-441}$ = $\sqrt{184}$ = $2\sqrt{46}$ Now, $\tan \theta=\frac{\text{Perpendicular}}{\text{Base}}=\frac{21}{2\sqrt{46}}$ Hence, the correct answer is $\frac{21}{2\sqrt{46}}$.
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Question : If $\theta$ is an acute angle and $\sin \theta \cos \theta=2 \cos ^3 \theta-\frac{1}{4} \cos \theta$, then the value of $\sin \theta$ is:
Option 1: $\frac{\sqrt{15}-1}{8}$
Option 2: $\frac{\sqrt{15}-1}{4}$
Option 3: $\frac{\sqrt{15}+1}{4}$
Option 4: $\frac{\sqrt{15}-1}{2}$
Question : If $\tan\theta+\sec\theta=3$, $\theta$ being acute, the value of $5\sin\theta$ is:
Option 1: $\frac{5}{2}$
Option 2: $\frac{\sqrt{3}}{5}$
Option 3: $\frac{5}{\sqrt{3}}$
Option 4: $4$
Question : If $\tan\theta =\frac{3}{4}$, then the value of $\frac{4\sin^{2}\theta–2\cos^{2}\theta}{4\sin^{2}\theta+3\cos^{2}\theta}$ is equal to:
Option 1: $\frac{1}{21}$
Option 2: $\frac{2}{21}$
Option 3: $\frac{4}{21}$
Option 4: $\frac{8}{21}$
Question : If $\theta$ is an acute angle and $\cos\theta=\frac{11}{17}$, what is the value of $\tan\theta$?
Option 1: $\frac{4 \sqrt{10}}{11}$
Option 2: $\frac{13}{11}$
Option 3: $\frac{2 \sqrt{42}}{11}$
Option 4: $\frac{2 \sqrt{42}}{17}$
Question : If $\sin 2\theta=\frac{\sqrt{3}}{2}$, then what is the value of $\tan \theta$?
Option 1: $\frac{1}{2}$
Option 2: $1$
Option 3: $\frac{1}{ \sqrt{3}}$
Option 4: $\sqrt{3}$
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