Question : If $\theta$ is an acute angle and $\sin \theta=\frac{43}{47}$, what is the value of $\cot \theta$?
Option 1: $\frac{6 \sqrt{10}}{47}$
Option 2: $\frac{43}{6 \sqrt{10}}$
Option 3: $\frac{47}{6 \sqrt{10}}$
Option 4: $\frac{6 \sqrt{10}}{43}$
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Correct Answer: $\frac{6 \sqrt{10}}{43}$
Solution : $\sin \theta = \frac{43}{47}$ $\therefore \cos \theta = \sqrt{1-\sin^2 \theta} = \sqrt{1-(\frac{43}{47})^2}$ = $\sqrt\frac{360}{47^2}$ = $\frac{6\sqrt{10}}{47}$ $\cot \theta = \frac{\cos\theta}{\sin \theta} = \frac{\frac{6\sqrt{10}}{47}}{\frac{43}{47}} = \frac{6\sqrt{10}}{43}$ Hence, the correct answer is $\frac{6\sqrt{10}}{43}$.
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Question : If $\theta$ is an acute angle and $\sin \theta \cos \theta=2 \cos ^3 \theta-\frac{1}{4} \cos \theta$, then the value of $\sin \theta$ is:
Option 1: $\frac{\sqrt{15}-1}{8}$
Option 2: $\frac{\sqrt{15}-1}{4}$
Option 3: $\frac{\sqrt{15}+1}{4}$
Option 4: $\frac{\sqrt{15}-1}{2}$
Question : If $\theta$ is an acute angle and $\sin \theta=\frac{13}{19}$, what is the value of $\cos \theta?$
Option 1: $\frac{6}{19}$
Option 2: $\frac{10 \sqrt{2}}{19}$
Option 3: $\frac{14}{19}$
Option 4: $\frac{8 \sqrt{3}}{19}$
Question : If $2(\cos^{2}\theta-\sin^{2}\theta)=1$; ($\theta$ is a positive acute angle), then $\cot\theta$ is equal to:
Option 1: $–\sqrt{3}$
Option 2: $\frac{1}{\sqrt{3}}$
Option 3: $1$
Option 4: $\sqrt{3}$
Question : If $\theta$ is an acute angle and $\sin \theta=\frac{21}{25}$, then what is the value of $\tan \theta$?
Option 1: $\frac{2 \sqrt{46}}{21}$
Option 2: $\frac{25}{2 \sqrt{46}}$
Option 3: $\frac{21}{2 \sqrt{46}}$
Option 4: $\frac{2 \sqrt{46}}{25}$
Question : If $\theta$ be an acute angle and $\tan \theta+\cot \theta=2$, then the value of $2 \tan ^2 \theta+\cot ^2 \theta+\tan ^4 \theta \cot ^4 \theta$ is:
Option 1: 4
Option 2: 2
Option 3: 3
Option 4: 6
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