Question : If $\frac{1}{6}$ of $x$ – $\frac{7}{2}$ of $\frac{3}{7}$ equals to $(-\frac{7}{4})$, then the value of $x$ is:
Option 1: –1.5
Option 2: –3
Option 3: –2.5
Option 4: 6
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Correct Answer: –1.5
Solution : Given: $\frac{1}{6}$ of $x$ – $\frac{7}{2}$ of $\frac{3}{7}$ equals to $(-\frac{7}{4})$. ⇒ $\frac{1}{6} × x-\frac{7}{2} ×\frac{3}{7}= -\frac{7}{4}$ ⇒ $\frac{x}{6} -\frac{3}{2}= -\frac{7}{4}$ ⇒ $\frac{x}{6} =-\frac{7}{4}+\frac{3}{2}$ ⇒ $\frac{x}{6} =-\frac{1}{4}$ ⇒ $x =-\frac{3}{2}$ ⇒ $x=-1.5$ Hence, the correct answer is –1.5.
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Question : If $(x+\frac{1}{x})^2=3$, then what is the value of $x^6 + x^{–6}$?
Option 1: 6
Option 2: 2
Option 3: –6
Option 4: –2
Question : If $(x+\frac{1}{x})=–2$, then the value of $(x^7+\frac{1}{x^7})$ is:
Option 1: 1
Option 2: –1
Option 3: 0
Question : If $(x-\frac{1}{x})^2=\sqrt3$, then the value of $(x^6+\frac{1}{x^6})$ equals:
Option 1: 90
Option 2: 100
Option 3: 110
Option 4: 120
Question : When $2x+\frac{2}{x}=3$, then the value of ($x^3+\frac{1}{x^3}+2)$ is:
Option 1: $\frac{2}{7}$
Option 2: $\frac{7}{8}$
Option 3: $\frac{7}{2}$
Option 4: $\frac{8}{7}$
Question : If $x+\frac{1}{x}=6$, then find the value of $\frac{3 x}{2 x^2-5 x+2}$.
Option 1: $1$
Option 2: $\frac{3}{7}$
Option 3: $\frac{2}{3}$
Option 4: $0$
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