Question : If r is the remainder when each of 4749, 5601, and 7092 is divided by the greatest possible number d(>1), then the value of (d + r) will be:
Option 1: 276
Option 2: 282
Option 3: 298
Option 4: 271
Correct Answer: 276
Solution : According to the question, d = HCF of (5601– 4749) and (7092 – 5601) = HCF of 852 and 1491 = 213 So, r = remainder [$\frac{4749}{213}$] = 63 The sum of (d + r) = 213 + 63 = 276 Hence, the correct answer is 276.
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Question : If $r$ is the remainder when each of 6454, 7306, and 8797 is divided by the greatest number $d(d>1)$, then $(d-r)$ is equal to:
Option 1: 126
Option 2: 64
Option 3: 137
Option 4: 149
Question : What is the greatest number of six digits, which when divided by each of 16, 24, 72, and 84 leaves the remainder 15?
Option 1: 999981
Option 2: 999951
Option 3: 999963
Option 4: 999915
Question : When a certain number is divided by 65, the remainder is 56. When the same number is divided by 13, the remainder is $x$. What is the value of $\sqrt{5x-2}$?
Option 1: $2 \sqrt{7}$
Option 2: $\sqrt{13}$
Option 3: $2 \sqrt{2}$
Option 4: $3 \sqrt{2}$
Question : Find the greatest number which when divided 261, 853, and 1221, leaves a remainder of 5 in each case.
Option 1: 19
Option 2: 18
Option 3: 17
Option 4: 16
Question : The greatest number by which 2300 and 3500 are divided, leaving the remainder of 32 and 56 respectively, is:
Option 1: 136
Option 2: 168
Option 3: 42
Option 4: 84
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