Question : If the angle of elevation of a cloud from a point 200 m above a lake is $30^\circ$ and the angle of depression of its reflection in the lake is $60^\circ$. Then the height of the cloud above the lake is:
Option 1: 100 m
Option 2: 200 m
Option 3: 300 m
Option 4: 400 m
Latest: SSC CGL 2024 final Result Out | SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL Tier 1 Scorecard 2024 Released | SSC CGL complete guide
Suggested: Month-wise Current Affairs | Upcoming Government Exams
Correct Answer: 400 m
Solution : Given: The angle of elevation of a cloud from a point 200 m above a lake is $30^\circ$ and the angle of depression of its reflection in the lake is $60^\circ$. Let the dotted line represent the lake, point C be the position of the cloud, point A is a point 200 m above the lake and C' is the reflection of the cloud in the lake. Also, let BC = $x$ m and AB = $y$ m. So, the height of the cloud above the lake is ($x$+200) m. In $\triangle$ABC, $\tan30°=\frac{x}{y}$ ⇒ $y=x\sqrt3$ --------------------(equation 1) In $\triangle$ABC', $\tan60°=\frac{x+200+200}{y}$ ⇒ $y\sqrt3=x+400$ ⇒ $(x\sqrt3)\sqrt3=x+400$ (putting the value of $y$ from equation 1) ⇒ $3x–x=400$ ⇒ $x=\frac{400}{2}$ ⇒ $x$ = 200 m. Hence, the correct answer is (200 + 200) = 400 m.
Candidates can download this ebook to know all about SSC CGL.
Admit Card | Eligibility | Application | Selection Process | Preparation Tips | Result | Answer Key
Question : The angle of elevation of an aeroplane as observed from a point 30 metres above the transparent water surface of a lake is 30° and the angle of the depression of the image of the aeroplane in the water of the lake is 60°. The height of the aeroplane from the water surface of the lake is:
Option 1: 60 metres
Option 2: 45 metres
Option 3: 50 metres
Option 4: 75 metres
Question : An aeroplane flying horizontally at a height of 3 km above the ground is observed at a certain point on earth to subtend an angle of $60^\circ$. After 15 seconds of flight, its angle of elevation is changed to $30^\circ$. The speed of the aeroplane (Take $\sqrt{3}=1.732$) is:
Option 1: 230.63 m/s
Option 2: 230.93 m/s
Option 3: 235.85 m/s
Option 4: 236.25 m/s
Question : The angle of elevation of an aeroplane from a point on the ground is 60°. After flying for 30 seconds, the angle of elevation changes to 30°. If the aeroplane is flying at a height of 4500 metres, then what is the speed (in m/s) of an aeroplane?
Option 1: $50\sqrt3$
Option 2: $100\sqrt3$
Option 3: $200\sqrt3$
Option 4: $300\sqrt3$
Question : A tower is broken at a point P above the ground. The top of the tower makes an angle of $60^\circ$ with the ground at Q. From another point R on the opposite side Q angle of elevation of point P is $30^\circ$. If QR = 180 m, what is the total height (in meters) of the tower?
Option 1: $90$
Option 2: $45\sqrt{3}$
Option 3: $45(\sqrt{3}+1)$
Option 4: $45(\sqrt{3}+2)$
Question : $D$ is a point on the side $BC$ of a triangle $ABC$ such that $AD\perp BC$. $E$ is a point on $AD$ for which $AE:ED=5:1$. If $\angle BAD=30^{\circ}$ and $\tan \left ( \angle ACB \right )=6\tan \left ( \angle DBE \right )$, then $\angle ACB =$
Option 1: $30^{\circ}$
Option 2: $45^{\circ}$
Option 3: $60^{\circ}$
Option 4: $15^{\circ}$
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile