Question : If the arithmetic mean of 7,5,13, $x$ and 9 is 10, then the value of $x$ is:
Option 1: 10
Option 2: 12
Option 3: 14
Option 4: 16
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Correct Answer: 16
Solution : We know, Mean = $\frac{\text{Sum of the numbers}}{\text{Total numbers in count}}$ ⇒ $10 =\frac{7+5+13+x+9}{5}$ ⇒ $10 =\frac{34+x}{5}$ ⇒ $50 = 34 +x$ $\therefore x = 16$ Hence, the correct answer is 16.
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Question : If $(x+\frac{1}{x})\neq 0$ and $(x^3+\frac{1}{x^3})= 0$, then the value $(x+\frac{1}{x})^4$ is:
Option 1: 9
Option 3: 15
Question : If $x+\frac{1}{x}=1$, then the value of $x^{12}+x^9+x^6+x^3+1$ is:
Option 1: 1
Option 2: - 1
Option 3: 0
Option 4: - 2
Question : If $14 : 30 :: 7 : x$, then what is the value of $x$?
Option 1: 15
Option 2: 21
Option 3: 9
Option 4: 12
Question : If $(x-\frac{1}{3})^2+(y-4)^2=0$, then what is the value of $\frac{y+x}{y-x}$?
Option 1: $\frac{11}{13}$
Option 2: $\frac{13}{11}$
Option 3: $\frac{16}{9}$
Option 4: $\frac{9}{16}$
Question : If $x=a^{\frac{1}{2}}+a^{-\frac{1}{2}}$, $y=a^{\frac{1}{2}}- a^{-\frac{1}{2}}$, then the value of $(x^{4}-x^{2}y^{2}-1)+(y^{4}-x^{2}y^{2}+1)$ is:
Option 1: 16
Option 2: 13
Option 3: 12
Option 4: 14
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