123 Views

If the line 2x+y-1=0,x-3y+k=0 are concurrent then k=


gangishettymanaswini 4th Oct, 2020
Answer (1)
Shefadaar 16th Oct, 2020

Hello there!

Lines are concurrent if they pass through a common point.

In order to find the value of k we have to find the value of x and y where both lines intersect.

Since, there are 3 variables (x,y and k) and we have only 2 equations. In this case, we can only find the value of k in terms of x or y.

Here is the approach:-

2x+y-1 = 0   ….eqn (1)

x-3y+k = 0   ….eqn (2)

Multiplying eqn (2) by 2 we get,

2x-6y+2k = 0   …eqn (3)


Subtracting eqn (1) from eqn (3) we get,

-7y+2k+1 = 0

From the above equation we get,

k = (7y-1)/2


Hope this answer resolves your query.

Related Questions

Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates and judiciaries
Amity University Noida B.Tech...
Apply
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations | AI Powered Learning & State-of-the-Art Facilities
Amity University Noida MBA Ad...
Apply
Amongst top 3% universities globally (QS Rankings) | Ranked among top 10 B-Schools in India by multiple publications
Amity University, Noida BBA A...
Apply
Ranked amongst top 3% universities globally (QS Rankings)
MAHE Online MBA
Apply
Apply for Online MBA from Manipal Academy of Higher Education (MAHE)
FLAME University | MBA 2026
Apply
NAAC A++ Grade | MBA program graded A** (National) by CRISIL | AACSB, ACBSP and BGA Member
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books