Question : If the radius of a sphere is decreased by 48%, then by what percentage does its surface area decrease?
Option 1: 82.91%
Option 2: 72.96%
Option 3: 78.98%
Option 4: 86.26%
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Correct Answer: 72.96%
Solution : Given: the radius of a sphere is decreased by 48%. Let the radius be $r$, then the surface area of the sphere = $4\pi r^2$ Now the radius has decreased by 48%, So, the radius = $r-0.48r$ = $0.52r$ And the new area = $4\pi (0.52r)^2$ = $4\pi r^2(0.2704)$ Therefore, the percentage decrease in surface area = $\frac{4\pi r^2-4\pi r^2(0.2704)}{4\pi r^2}×100$ = $72.96\%$ Hence, the correct answer is 72.96%.
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Question : If the surface area of a sphere is 346.5 cm2, then its radius is: (Take $\pi=\frac{22}{7}$)
Option 1: 7 cm
Option 2: 3.25 cm
Option 3: 5.25 cm
Option 4: 9 cm
Question : If the radius of a sphere is increased by 2.5 decimetres (dm), then its surface area increases by 110 dm$^2$. What is the volume (in dm$^3$ ) of the sphere? (Take $\pi=\frac{22}{7}$)
Option 1: $\frac{13}{21}$
Option 2: $\frac{3}{7}$
Option 3: $\frac{4}{7}$
Option 4: $\frac{11}{21}$
Question : Water tax is increased by 20% but its consumption is decreased by 20%. Then, the increase or decrease in the expenditure of money is:
Option 1: 5% decrease
Option 2: 4% decrease
Option 3: No change
Option 4: 4% increase
Question : If the radius of a right circular cylinder open at both ends is decreased by 25% and the height of the cylinder is increased by 25%, the curved surface area of the cylinder thus formed:
Option 1: remains unaltered
Option 2: is increased by $25\%$
Option 3: is increased by $6.25\%$
Option 4: is decreased by $6.25\%$
Question : A solid metallic sphere of radius 4 cm is melted and recast into spheres of 2 cm each. What is the ratio of the surface area of the original sphere to the sum of the surface areas of the spheres, so formed?
Option 1: 2 : 1
Option 2: 2 : 3
Option 3: 1 : 2
Option 4: 1 : 4
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