Question : If the sides of a triangle are extended on both sides then the sum of the exterior angles formed on both sides is:
Option 1: $360^{\circ}$
Option 2: $540^{\circ}$
Option 3: $720^{\circ}$
Option 4: $180^{\circ}$
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Correct Answer: $720^{\circ}$
Solution : $\angle$ABC + $\angle$BCA + $\angle$BAC = $180^{\circ}$ ---------------(i) ⇒ $\angle$ACB + $\angle$ACD = $180^{\circ}$ ---------------(ii) ⇒ $\angle$ABC + $\angle$ABF = $180^{\circ}$ ---------------(iii) ⇒ $\angle$BAC + $\angle$EAC = $180^{\circ}$ ---------------(iv) Adding (ii), (iii), and (iv), then subtracting (i) from it, $\therefore$ $\angle$ACD + $\angle$ABF + $\angle$EAC = $540^{\circ}$ – $180^{\circ}$ = $360^{\circ}$ So, the sum of the exterior angles formed on both sides = $2 × 360^{\circ}$ = $720^{\circ}$ Hence, the correct answer is $720^{\circ}$.
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Question : The exterior angles obtained on producing the base $BC$ of a $\triangle ABC$ in both ways are $120^{\circ}$ and $105^{\circ}$, then the vertical $\angle A$ of the triangle is:
Option 1: $36^{\circ}$
Option 2: $40^{\circ}$
Option 3: $45^{\circ}$
Option 4: $55^{\circ}$
Question : In an isosceles triangle, if the unequal angle is 4 times the sum of the equal angles, then each equal angle is:
Option 1: $25^{\circ}$
Option 2: $30^{\circ}$
Option 3: $21^{\circ}$
Option 4: $18^{\circ}$
Question : In an isosceles triangle, if the unequal angle is five times the sum of the equal angles, then each equal angle is:
Option 1: $45^\circ$
Option 2: $60^\circ$
Option 3: $15^\circ$
Option 4: $30^\circ$
Question : Three angles of a triangle are $(x-15^{\circ}),(x+45^{\circ}),$ and $(x+60^{\circ})$. Identify the type of triangle.
Option 1: Obtuse angle triangle
Option 2: Right angle triangle
Option 3: Isosceles triangle
Option 4: Equilateral triangle
Question : In a triangle ABC, two angles A and B are equal. If the exterior angle is at $\angle A = 115°$, find the measure of $\angle C$.
Option 1: $50^{\circ}$
Option 2: $130^{\circ}$
Option 3: $115^{\circ}$
Option 4: $65^{\circ}$
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