Question : If $\sec \theta+\tan \theta=4$, then $\sec \theta-\tan \theta=$___________.
Option 1: $\frac{1}{4}$
Option 2: $\frac{1}{2}$
Option 3: 2
Option 4: 4
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Correct Answer: $\frac{1}{4}$
Solution : Given, $\sec \theta+\tan \theta=4$ We know that, $\sec^2\theta-\tan^2\theta = 1$ ⇒ $(\sec\theta-\tan\theta)(\sec\theta+\tan\theta)=1$ ⇒ $(\sec\theta-\tan\theta)(4)=1$ $\therefore\sec\theta-\tan\theta=\frac{1}{4}$ Hence, the correct answer is $\frac{1}{4}$.
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Question : If $\sec\theta +\tan\theta = 3$, then what is the value of $\sec \theta-\tan \theta$?
Option 1: $\frac{1}{3}$
Option 2: $6$
Option 3: $\frac{1}{6}$
Option 4: $\frac{1}{5}$
Question : If $\sec \theta-\tan \theta=m$, then $2 \tan \theta=?$
Option 1: $\frac{1-m}{m} \\$
Option 2: $ \frac{1-m^2}{m} \\$
Option 3: $\frac{1+m^2}{m} \\$
Option 4: $ \frac{m^2-1}{m}$
Question : If $\sqrt{2} \sec ^2 \theta-4 \sec \theta+2 \sqrt{2}=0$, then what is the value $\sin ^2 \theta+\tan ^2 \theta$?
Option 1: $\frac{1}{2}$
Option 2: $\frac{2}{3}$
Option 3: $\frac{5}{2}$
Option 4: $\frac{3}{2}$
Question : If $\sec\theta+\tan\theta=a$, then what is the value of $\sec\theta$?
Option 1: $\frac{a+1}{2a^2}$
Option 2: $\frac{(a-1)}{2a^2}$
Option 3: $\frac{a^2-1}{2a}$
Option 4: $\frac{a^2+1}{2a}$
Question : If $\sqrt{3} \tan ^2 \theta-4 \tan \theta+\sqrt{3}=0$, then what is the value of $\tan ^2 \theta+\cot ^2 \theta$?
Option 1: $\frac{4}{3}$
Option 2: $\frac{10}{3}$
Option 3: $3$
Option 4: $\frac{6}{5}$
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