Question : If $(x–4)(x^2+4x+16)=x^3–p$, then $p$ is equal to:
Option 1: 27
Option 2: 8
Option 3: 64
Option 4: 0
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Correct Answer: 64
Solution : Given: $(x–4)(x^2+4x+16)=x^3–p$ Formula: We know that $a^3–b^3=(a–b)(a^2+ab+b^2)$ Solution: $x^3–p=(x–4)(x^2+4x+16)$ ⇒ $x^3−p=(x^3−4^3)$ ⇒ $p = 4^3$ So, $p = 64$. Hence, the correct answer is 64.
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Question : A complete factorisation of $(x^4+64)$ is:
Option 1: $(x^2+8)^2$
Option 2: $(x^2+8)$$(x^2-8)$
Option 3: $(x^2-4x+8)(x^2-4x-8)$
Option 4: $(x^2+4x+8)$$(x^2-4x+8)$
Question : If $x$,$y$ and $z$ are real numbers such that $(x-3)^2+(y-4)^2+(z-5)^2=0$, then $(x+y+z)$ is equal to:
Option 1: –12
Option 2: 0
Option 3: 8
Option 4: 12
Question : If $x=\sqrt{–\sqrt{3}+\sqrt{3+8 \sqrt{7+4 \sqrt{3}}}}$ where $x > 0$, then the value of $x$ is equal to:
Option 1: 3
Option 2: 4
Option 3: 1
Option 4: 2
Question : If $x+y=1+xy$, then $x^3+y^3-x^3y^3$ is equal to:
Option 1: 0
Option 2: 1
Option 3: –1
Question : If $(x-5)^2+(y-2)^2+(z-9)^2=0$, then value of $(x+y-z)$ is:
Option 1: 16
Option 2: –1
Option 3: –2
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