Question : If $\left(\mathrm{k}+\frac{1}{\mathrm{k}}\right)^2=9$, then what is the value of $\mathrm{k}^3+\frac{1}{\mathrm{k}^3} ?$

Option 1: 27

Option 2: 18

Option 3: 15

Option 4: 21

Question : What is the value of $\left(k-\frac{1}{k}\right)\left(k^2+\frac{1}{k^2}\right)\left(k^4+\frac{1}{k^4}\right)\left(k^8+\frac{1}{k^8}\right)\left(k^{16}+\frac{1}{k^{16}}\right) ?$

Option 1: $k^{64}-\frac{1}{k^{64}}$

Option 2: $\frac{k^{32}-\frac{1}{k^{32}}}{k-\frac{1}{k}}$

Option 3: $k^{32}-\frac{1}{k^{32}}$

Option 4: $\frac{k^{32}-\frac{1}{k^{32}}}{k+\frac{1}{k}}$

Question : If $x=(\sqrt{6}-1)^{\frac{1}{3}}$, then the value of $\left(x-\frac{1}{x}\right)^3+3\left(x-\frac{1}{x}\right)$ is:

Option 1: $\frac{2 \sqrt{6}-6}{5}$

Option 2: $\frac{4 \sqrt{6}-6}{5}$

Option 3: $\frac{4 \sqrt{6}-6}{3}$

Option 4: $\frac{4 \sqrt{3}-6}{5}$

Question : If $\left(a+\frac{1}{a}\right)=6$, then what is the value of $\frac{3}{4}\left(a^2+\frac{1}{a^2}\right)$?

Option 1: 22.5

Option 2: 34

Option 3: 25.5

Option 4: 36

Question : What is the value of $\left(\mathrm{k}+\frac{1}{\mathrm{k}}\right)\left(\mathrm{k}-\frac{1}{\mathrm{k}}\right)\left(\mathrm{k}^2+\frac{1}{\mathrm{k}^2}\right)\left(\mathrm{k}^4+\frac{1}{\mathrm{k}^4}\right)$?

Option 1: $\mathrm{k}^{16}+\frac{1}{\mathrm{k}^{16}}$

Option 2: $\mathrm{k}^{16}-\frac{1}{\mathrm{k}^{16}}$

Option 3: $\mathrm{k}^8-\frac{1}{\mathrm{k}^8}$

Option 4: $\mathrm{k}^8+\frac{1}{\mathrm{k}^8}$