Question : If $3 \tan \theta=4$, then what is the value of $7 \sin \theta-2 \cos \theta$?
Option 1: $\frac{12}{5}$
Option 2: $4$
Option 3: $\frac{22}{5}$
Option 4: $\frac{17}{5}$
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Correct Answer: $\frac{22}{5}$
Solution : Given, $3 \tan \theta=4$ ⇒ $\tan\theta=\frac43=\frac{\text{Perpendicular}}{\text{Base}}$ Using the Pythagoras theorem, $\small\text{Hypotenuse}^2=\text{Perpendicular}^2+\text{Base}^2$ ⇒ $h^2=4^2+3^2$ ⇒ $h^2=16+9$ ⇒ $h^2=25$ ⇒ $h=5$ We know, $\sin\theta=\frac{\text{Perpendicular}}{\text{Hypotenuse}}$ and $\cos\theta=\frac{\text{Base}}{\text{Hypotenuse}}$ ⇒ $\sin\theta=\frac{4}{5}$ and $\cos\theta=\frac35$ So, $7 \sin \theta-2 \cos \theta=7\times\frac{4}{5}-2\times\frac{3}{5}=\frac{28}{5}-\frac{6}{5}=\frac{22}{5}$ Hence, the correct answer is $\frac{22}{5}$.
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Question : If $\sin \theta-\cos \theta=\frac{1}{5}$, then find the value of $\sin \theta+\cos \theta$.
Option 1: $\frac{5}{7}$
Option 2: $\frac{7}{5}$
Option 3: $\frac{5}{3}$
Option 4: $\frac{3}{5}$
Question : If $\frac{\sin\theta+\cos\theta}{\sin\theta-\cos\theta}=3$, then the value of $\sin^{4}\theta$ is:
Option 1: $\frac{2}{5}$
Option 2: $\frac{1}{5}$
Option 3: $\frac{16}{25}$
Question : If $\sin \theta-\cos \theta=0$, then what is the value of $\sin ^2 \theta+\tan ^2 \theta$ ?
Option 1: $\frac{1}{2}$
Option 2: $1$
Option 3: $\frac{4}{5}$
Option 4: $\frac{3}{2}$
Question : If $5\tan\theta=4$, then $\frac{5\sin\theta-3\cos\theta}{5\sin\theta+2\cos\theta}$ is equal to:
Option 1: $\frac{2}{3}$
Option 2: $\frac{1}{4}$
Option 3: $\frac{1}{6}$
Option 4: $\frac{1}{3}$
Question : What is the value of $\frac{\sin \theta+\cos \theta}{\sin \theta-\cos \theta}+\frac{\sin \theta-\cos \theta}{\sin \theta+\cos \theta}$?
Option 1: $\frac{1}{\left(\sin ^2 \theta-\cos ^2 \theta\right)}$
Option 2: $2\left(\sin ^2 \theta-\cos ^2 \theta\right)$
Option 3: $\frac{2}{\left(\sin ^2 \theta-\cos ^2 \theta\right)}$
Option 4: $\sin ^2 \theta-\cos ^2 \theta$
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