Question : If X = 600 and Y = 800, then X is how much percentage less than Y?
Option 1: 33.33%
Option 2: 25%
Option 3: 75%
Option 4: 35%
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 25%
Solution : Given: X = 600 and Y = 800 Required percentage = $\frac{\text{Difference}}{\text{Value of Y}}$ × 100% = $\frac{800–600}{800}$ × 100% =$\frac{200}{800}$ × 100% = 25% Hence, the correct answer is 25%.
Candidates can download this e-book to give a boost to thier preparation.
Application | Eligibility | Admit Card | Answer Key | Preparation Tips | Result | Cutoff
Question : If $X$ is 20% less than $Y$, then find the values of$\frac{Y–X}{Y}$ and $\frac{X}{X–Y}$.
Option 1: $\frac{1}{5}$ and $-4$
Option 2: $5$ and $-\frac{1}{4}$
Option 3: $\frac{2}{5}$ and $-\frac{5}{2}$
Option 4: $\frac{3}{5}$ and $-\frac{5}{3}$
Question : Simplify the given expression $\frac{(x^3-y^3)(x+y)}{x^2+x y+y^2}$.
Option 1: $x - y$
Option 2: $x^2-y^2$
Option 3: $x + y$
Option 4: $x^2+y^2$
Question : If $x=\operatorname{cosec \theta}-\sin\theta$ and $y=\sec\theta-\cos\theta$, then the relation between $x$ and $y$ is:
Option 1: $x^{2}+y^{2}+3=1$
Option 2: $x^{2}y^{2}\left ( x^{2}+y^{2}+3 \right )=1$
Option 3: $x^{2}\left ( x^{2}+y^{2}-5 \right )=1$
Option 4: $y^{2}\left ( x^{2}+y^{2}-5 \right )=1$
Question : If $x$ = $y$ = $z$, then $\frac{\left (x+y+z \right )^{2}}{x^{2}+y^{2}+z^{2}}$ is equal to:
Option 1: 4
Option 2: 2
Option 3: 3
Option 4: 1
Question : If $2 x+5 y=15$ and $x y=6$, then the value of $4 x^2+25 y^2$ is:
Option 1: 105
Option 2: 95
Option 3: 100
Option 4: 90
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile