Question : If x + y = √3 and x – y = √2, the value of 8xy(x2 + y2) is:
Option 1: 6
Option 2: √6
Option 3: 5
Option 4: √5
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Correct Answer: 5
Solution : According to the question, x + y = √3 Squaring both sides, we get, ⇒ x2 + y2 + 2xy = 3 ––––––––––––(i) Now, x – y = √2 Squaring both sides, we get, ⇒ x2 + y2 – 2xy = 2 ––––––––––––(ii) Adding equations (i) and (ii), we get, 2x2 + 2y2 = 5 ⇒ x2 + y2 = $\frac{5}{2}$ ––––––––––––––––(iii) Now putting the value from equation (iii) in equation (i), we get, $\frac{5}{2}$ + 2xy = 3 ⇒ 2xy = 3 – $\frac{5}{2}$ ⇒ 2xy = $\frac{1}{2}$ $\therefore$ xy = $\frac{1}{4}$ Now, the value of 8xy(x2 + y2) = $8 × \frac{1}{4} × \frac{5}{2}$ = $5$ Hence, the correct answer is 5.
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Question : What is the value of (3x3 + 5x2y + 12xy2 + 7y3), when x = – 4 and y = – 1?
Option 1: – 329
Option 2: – 359
Option 3: – 361
Option 4: – 327
Question : If $xy = -6$ and $x^3+ y^3= 19$ ($x$ and $y$ are integers), then what is the value of $\frac{1}{x^{–1}}+\frac{1}{y^{–1}}$?
Option 1: –1
Option 2: –2
Option 3: 1
Option 4: 2
Question : If the HCF of xy3, x2 y, and x3 y4 is xy, then their LCM is________.
Option 1: x3 y4
Option 2: x3 y3
Option 3: x4 y3
Option 4: x4 y4
Question : If $x+y+z=0$ and $x^2+y^2+z^2=40$, then what is the value of $x y+y z+z x?$
Option 1: –20
Option 2: 5
Option 3: –5
Option 4: –10
Question : If $4x–7y=3$ and $2x–y=9$, then the value of $(x–y)$ is:
Option 1: 3
Option 2: 4
Option 4: 6
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