Question : In a school, 391 boys and 323 girls have been divided into the largest possible equal classes, so that each class of boys numbers the same as each class of girls. What is the number of classes?
Option 1: 23
Option 2: 19
Option 3: 42
Option 4: 17
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Correct Answer: 42
Solution : Given: 391 Boys and 323 Girls in the class. Prime factors of 391 = (17 × 23) Prime factors of 323 = (17 × 19) HCF of (391, 323) = 17 The largest possible equal number of students in each class = 17 Now, find the number of classes of boys when there are 391 boys $⇒\frac{391}{17}=23$ Similarly, the number of classes of girls when there are 323 girls, $⇒ \frac{323}{17}=19$ Then, total number of classes = (23 + 19) = 42 Hence, the correct answer is 42.
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Question : The ratio of boys and girls in a school is 27 : 23. If the difference between the number of boys and girls is 200, then find the number of boys.
Option 1: 1350
Option 2: 1250
Option 3: 1300
Option 4: 1200
Question : The HCF of two numbers is 17 and the other two factors of their LCM are 11 and 19. The smaller of the two numbers is:
Option 1: 209
Option 2: 187
Option 3: 323
Option 4: 306
Question : The ratio of the number of boys in a school to the total number of boys and girls in that school is 7 : 17. If the number of boys in that school is 1099, then how many girls are there in that school?
Option 1: 1570
Option 2: 1580
Option 3: 1560
Option 4: 1550
Question : Find the fourth proportional to the numbers 17, 272, and 19.
Option 1: 332
Option 2: 323
Option 3: 403
Option 4: 304
Question : The arithmetic mean of the following data is _________. 23, 17, 20, 19, 21
Option 1: 20
Option 3: 23
Option 4: 21
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