Question : In a test consisting of 140 questions, a candidate correctly answered 70% of the first 80 questions. What percentage of the remaining questions does the candidate need to correctly answer to score 60% on the test?
Option 1: $35\%$
Option 2: $46 \frac{2}{3}\%$
Option 3: $45 \frac{1}{3}\%$
Option 4: $40\%$
Correct Answer: $46 \frac{2}{3}\%$
Solution : According to the question, Correctly answered in first 80 questions = 0.7 × 80 = 56 Remaining questions = 140 − 80 = 60 Target correct answers = 0.6 × 140 = 84 Now, Remaining correct answers needed = Target correct answers − Correctly answered = 84− 56 = 28 Required percentage $=\frac{\text{28}}{\text{60}} ×100 = 46 \frac{2}{3}\%$ Hence, the correct answer is $46 \frac{2}{3}\%$.
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Question : In a test consisting of 120 questions, Anuradha answered 65% of the first 60 questions correctly. What percentage of the remaining questions does she need to answer correctly to score 75% in the test?
Option 1: 80
Option 2: 85
Option 3: 84
Option 4: 90
Question : The value of $\frac{\sin ^2 30^{\circ}+\cos ^2 60^{\circ}+\sec 45^{\circ} × \sin 45^{\circ}}{\sec 60^{\circ}+{\text{cosec}} 30^{\circ}}$ is:
Option 1: $\frac{1}{4}$
Option 2: $-\frac{3}{8}$
Option 3: $\frac{3}{8}$
Option 4: $-\frac{1}{4}$
Question : If $a-\frac{1}{a-5}=10$, then the value of $(a-5)^3-\frac{1}{(a-5)^3}$ is:
Option 1: 140
Option 2: 70
Option 3: 100
Option 4: 120
Question : The HCF of $\frac{3}{4}, \frac{7}{8}$, and $\frac{13}{14}$ is:
Option 1: $\frac{1}{36}$
Option 2: $\frac{1}{56}$
Option 3: $\frac{1}{70}$
Option 4: $\frac{1}{60}$
Question : The ratio of the number of boys and girls in a school is 3 : 4 respectively. If the number of boys increases by 10% and the number of girls increases by 15%, what will be the new ratio of the number of boys to the number of girls?
Option 1: $\frac{33}{45}$
Option 2: $\frac{35}{46}$
Option 3: $\frac{33}{46}$
Option 4: $\frac{46}{33}$
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