Question : In an equilateral triangle, the circumradius is 14 cm. What is the length of the median in this triangle?
Option 1: $14 \sqrt{3} \mathrm{~cm}$
Option 2: $21 \mathrm{~cm}$
Option 3: $18 \sqrt{3} \mathrm{~cm}$
Option 4: $7 \sqrt{3} \mathrm{~cm}$
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Correct Answer: $21 \mathrm{~cm}$
Solution : Circumradius = 14 cm $a$ = side of equilateral triangle Circum-radius, r = $\frac{a}{\sqrt{3}}$ ⇒ $a = 14\sqrt{3}$ cm Now, Length of median = Height of equilateral triangle $ = \frac{\sqrt{3}a}{2}= \frac{(\sqrt{3} × 14\sqrt{3})}{2}$ = 21 cm Hence, the correct answer is $21 \mathrm{~cm}$.
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Question : In an equilateral triangle STU, inradius is $5 \sqrt{3 }\mathrm{~cm}$. What is the length of the side of this equilateral triangle?
Option 1: $20 \sqrt{3} \mathrm{~cm}$
Option 2: $18 \sqrt{3} \mathrm{~cm}$
Option 3: $30 \mathrm{~cm}$
Option 4: $24 \mathrm{~cm}$
Question : The median of an equilateral triangle is $15 \sqrt{3} \mathrm{~cm}$. What is the side of this triangle?
Option 1: 24 cm
Option 2: 18 cm
Option 3: 30 cm
Option 4: 36 cm
Question : Find the area of an equilateral triangle whose sides are 12 cm.
Option 1: $38 \sqrt{3} \mathrm{~cm}^2$
Option 2: $35 \sqrt{3} \mathrm{~cm}^2$
Option 3: $34 \sqrt{3} \mathrm{~cm}^2$
Option 4: $36 \sqrt{3} \mathrm{~cm}^2$
Question : The sides of a triangle are 9 cm, 6 cm, and 5 cm. What is the value of the circumradius of this triangle?
Option 1: $\frac{9 \sqrt{2}}{2} \mathrm{~cm}$
Option 2: $\frac{9 \sqrt{3}}{5} \mathrm{~cm}$
Option 3: $\frac{9 \sqrt{3}}{4} \mathrm{~cm}$
Option 4: $\frac{27 \sqrt{2}}{8} \mathrm{~cm}$
Question : The three sides of a triangle are 7 cm, 9 cm, and 8 cm. What is the area of the triangle?
Option 1: $12 \sqrt{3} \;\mathrm{Sq} . \mathrm{cm}$
Option 2: $10\sqrt{3} \;\mathrm{Sq} . \mathrm{cm}$
Option 3: $12 \sqrt{5} \;\mathrm{Sq} . \mathrm{cm}$
Option 4: $2 \sqrt{5} \;\mathrm{Sq} . \mathrm{cm}$
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