Question : In $\triangle \mathrm{PQR}, \angle \mathrm{Q}=90$°, and QX is perpendicular to PR. If PQ = 15 cm and PR = 25 cm, what is the PX : XR ratio?
Option 1: 2 : 3
Option 2: 7 : 18
Option 3: 1 : 4
Option 4: 9 : 16
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Correct Answer: 9 : 16
Solution : If a perpendicular is drawn from the vertex of the right angle of a right-angled triangle to the hypotenuse, then it divides the hypotenuse into two segments. The lengths of these segments are proportional to the lengths of the other two sides. This is based on the principle of similar triangles. Using the principle of similar triangles, since $\triangle$PQR ~ $\triangle$PQX, we have: $\frac{PX}{PQ}$ = $\frac{PQ}{PR}$ Plugging in the given values: $\frac{PX}{15}$ = $\frac{15}{25}$ $\therefore$ PX = 9 cm So, XR = PR – PX = 25 – 9 = 16 Therefore, the ratio of PX to XR is 9 : 16. hence, the correct answer is 9 : 16.
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Question : It is given that $\triangle \mathrm{PQR} \cong \triangle \mathrm{MNY}$ and $PQ=8\ \mathrm{cm}, \angle Q = 55°$ and $\angle P = 72°$. Which of the following is true?
Option 1: $\mathrm{NY}=8 \mathrm{~cm}, \angle \mathrm{Y}=72^{\circ}$
Option 2: $\mathrm{NM}=8 \mathrm{~cm}, \angle \mathrm{M}=53^{\circ}$
Option 3: $\mathrm{NM}=8 \mathrm{~cm}, \angle \mathrm{Y}=53^{\circ}$
Option 4: $\mathrm{NY}=8 \mathrm{~cm}, \angle \mathrm{N}=55^{\circ}$
Question : In $\triangle \mathrm{PQR}, \angle \mathrm{P}=46^{\circ}$ and $\angle \mathrm{R}=64^{\circ}$.If $\triangle \mathrm{PQR}$ is similar to $\triangle \mathrm{ABC}$ and in correspondence, then what is the value of $\angle \mathrm{B}$?
Option 1: 70°
Option 2: 90°
Option 3: 100°
Option 4: 110°
Question : Two similar triangles are given i.e. $\triangle$LMN ~ $\triangle$PQR, with measurement of angle and side as $\angle$ L = 40°, $\angle$ N = 80°, LM = 6 cm, LN = 8 cm and PQ = 7.5 cm. Find the value of $\angle$ Q and side PR, respectively.
Option 1: 60° and 20 cm
Option 2: 50° and 6.5 cm
Option 3: 40° and 10 cm
Option 4: 60° and 10 cm
Question : O is the incentre of the $\triangle \mathrm{PQR}$. If $\angle \mathrm{POR}=120°$, then what is the $\triangle \mathrm{PQR}$?
Option 1: 45°
Option 2: 60°
Option 3: 55°
Option 4: 48°
Question : $\triangle P Q R$ is similar to $\triangle \mathrm{UVW}$. Perimeters of $\triangle \mathrm{PQR}$ and $\Delta \mathrm{UVW}$ are 120 cm and 240 cm respectively. If PQ = 30 cm, then what is the length of UV?
Option 1: 45 cm
Option 2: 75 cm
Option 3: 60 cm
Option 4: 90 cm
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