Question : In $\triangle ABC, DE \parallel BC$ in such a way that $A-D-B$ and $A-E-C$ are equal. If $ \angle A C B=40°$, then $\angle D A E+\angle ADE =$ ___________.
Option 1: 240°
Option 2: 120°
Option 3: 140°
Option 4: 230°
Correct Answer: 140°
Solution : Given, A triangle ABC in which DE || BC. Here, we have a triangle ABC in which DE $\parallel$ BC ⇒ The $\angle$ACB = $\angle$AED = 40° (corresponding angles as DE$\parallel$BC and AC is a transversal line which intersects them) Now, consider the $\triangle$ADE as we know that, The sum of the angles of a triangle $= 180°$ ⇒ $\angle ADE +\angle DAE + \angle AED = 180 °$ ⇒ $\angle ADE +\angle DAE + 40 ° = 180 °$ $\therefore\angle ADE + \angle DAE = 140 °$ Hence, the correct answer is 140°.
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Question : $\triangle \mathrm{ABC}$ and $\triangle \mathrm{DEF}$ are two triangles such that $\triangle \mathrm{ABC} \cong \triangle \mathrm{FDE}$. If AB = 5 cm, $\angle$B = 40° and $\angle$A = 80°, then which of the following options is true?
Option 1: DF = 5 cm, $\angle$E = 60°
Option 2: DE = 5 cm, $\angle$F = 60°
Option 3: DE = 5 cm, $\angle$D = 60°
Option 4: DE = 5 cm, $\angle$E = 60°
Question : In $\triangle A B C, \mathrm{BD} \perp \mathrm{AC}$ at $\mathrm{D}$. $\mathrm{E}$ is a point on $\mathrm{BC}$ such that $\angle B E A=x^{\circ}$. If $\angle E A C=46^{\circ}$ and $\angle E B D=60^{\circ}$, then the value of $x$ is:
Option 1: 72°
Option 2: 78°
Option 3: 68°
Option 4: 76°
Question : In $\triangle A B C $, AB and AC are produced to points D and E, respectively. If the bisectors of $\angle C B D$ and $\angle B C E$ meet at the point O, and $\angle B O C=57^{\circ}$, then $\angle A$ is equal to:
Option 1: 93°
Option 2: 66°
Option 3: 114°
Option 4: 57°
Question : In a triangle, ABC, BC is produced to D so that CD = AC. If $\angle BAD=111^{\circ}$ and $\angle ACB=80^{\circ}$, then the measure of $\angle ABC$ is:
Option 1: 31°
Option 2: 33°
Option 3: 35°
Option 4: 29°
Question : In a $\triangle ABC$, D and E are two points on AB and AC respectively such that DE || BC, DE bisects the $\triangle ABC$ in two equal areas. Then the ratio DB : AB is:
Option 1: $1:\sqrt2$
Option 2: $1:2$
Option 3: $\left ( \sqrt2-1 \right ):\sqrt2$
Option 4: $\sqrt2:1$
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