Question : In $\triangle A B C,$ P and Q are the middle points of the sides AB and AC, respectively. R is the point on the segment PQ such that PR : RQ = 1 : 3. If PR = 6 cm, then BC is:
Option 1: 46 cm
Option 2: 48 cm
Option 3: 44 cm
Option 4: 50 cm
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Correct Answer: 48 cm
Solution : Given, PR ∶ RQ = 1 ∶ 3 and PR = 6 cm Let the PR and RQ be $x$ and $3x$ respectively. According to the question, ⇒ PR = $x$ = 6 cm [Given] ⇒ RQ = $3x$ = 3 $×$ 6 = 18 cm Now, ⇒ PQ = (PR + RQ) ⇒ PQ = (6 + 18) cm ⇒ PQ = 24 cm We know that the line joining the midpoints of two sides of a triangle is parallel and half of the third side. So, BC = 2PQ = 2 $×$ 24 = 48 cm Hence, the correct answer is 48 cm.
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Question : If in a $\triangle$PQR, $\angle$P = $88^\circ$, PQ and PR are produced to points S and T respectively. If the bisectors of $\angle$SQR and $\angle$TRQ meet at the point O. Find $\angle$QOR.
Option 1: $42^\circ$
Option 2: $46^\circ$
Option 3: $44^\circ$
Option 4: $48^\circ$
Question : $\triangle P Q R$ is similar to $\triangle \mathrm{UVW}$. Perimeters of $\triangle \mathrm{PQR}$ and $\Delta \mathrm{UVW}$ are 120 cm and 240 cm respectively. If PQ = 30 cm, then what is the length of UV?
Option 1: 45 cm
Option 2: 75 cm
Option 3: 60 cm
Option 4: 90 cm
Question : Two circles touch each other externally at any point C. PQ is the direct common tangent to both the circles touching the circles at point P and point Q. If the radii of the circles are 36 cm and 16 cm, respectively, then the length of PQ is:
Option 1: 42 cm
Option 2: 24 cm
Option 3: 48 cm
Option 4: 36 cm
Question : The perimeters of two similar triangles $\triangle$ABC and $\triangle$PQR are 36 cm and 24 cm respectively. If PQ = 10 cm, then AB is:
Option 1: 15 cm
Option 2: 12 cm
Option 3: 14 cm
Option 4: 26 cm
Question : If in a $\triangle$ABC, D and E are on the sides AB and AC, such that, DE is parallel to BC and $\frac{AD}{BD}$ = $\frac{3}{5}$. If AC = 4 cm, then AE is:
Option 1: 1.5 cm
Option 2: 2.0 cm
Option 3: 1.8 cm
Option 4: 2.4 cm
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