Question : In the given figure, ABCDEF is a regular hexagon whose side is 6 cm. APF, QAB, DCR, and DES are equilateral triangles. What is the area (in cm2) of the shaded region?
Option 1: $24\sqrt{3}$
Option 2: $18\sqrt{3}$
Option 3: $72\sqrt{3}$
Option 4: $36\sqrt{3}$
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Correct Answer: $72\sqrt{3}$
Solution : Given that ABCDEF is a regular hexagon with a side length of 6 cm, and APF, QAB, DCR, and DES are equilateral triangles. The area of an equilateral triangle = $\frac{\sqrt{3}}{4} s^2 $ where $s$ is the side length of the triangle. On substituting $s$ = 6 cm. The area of an equilateral triangle APF = $\frac{\sqrt{3}}{4} (6)^2 = 9\sqrt{3} $ cm2 Area of quadrilateral ABOF = 2 × Area of an equilateral triangle APF ⇒ Area of quadrilateral ABOF = $18\sqrt{3} $ cm2 Similarly, of the area of quadrilateral DCOE = 2 × Area of an equilateral triangle EDS ⇒ Area of quadrilateral DCOE = $18\sqrt{3} $ cm2 The area of the shaded region = Area of quadrilateral ABOF + Area of quadrilateral DCOE + 4 × Area of an equilateral triangle APF ⇒ The area of the shaded region = $18\sqrt{3} +18\sqrt{3} +36\sqrt{3} =72\sqrt{3} $ cm2 Hence, the correct answer is $72\sqrt{3} $.
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Question : The height of an equilateral triangle is $7 \sqrt{3}$ cm. What is the area of this equilateral triangle?
Option 1: $36 \sqrt{3}$ cm2
Option 2: $25 \sqrt{3}$ cm2
Option 3: $49 \sqrt{3}$ cm2
Option 4: $32 \sqrt{3}$ cm2
Question : ABCDEF is a regular hexagon. The side of the hexagon is 36 cm. What is the area of the $\triangle ABC$?
Option 1: $324 \sqrt{3}\ {cm}^2$
Option 2: $360 \sqrt{3} \ {cm}^2$
Option 3: $240 \sqrt{3} \ {cm}^2$
Option 4: $192 \sqrt{3} \ {cm}^2$
Question : ABCDEF is a regular hexagon of side 12 cm. What is the area (in cm2) of the $\triangle $ECD?
Option 1: $18\sqrt{3}$
Option 2: $24\sqrt{3}$
Option 3: $36\sqrt{3}$
Option 4: $42\sqrt{3}$
Question : The base of a right prism is an equilateral triangle whose side is 10 cm. If the height of this prism is $10 \sqrt{3}$ cm, then what is the total surface area of the prism?
Option 1: $125 \sqrt{3}$ cm2
Option 2: $325 \sqrt{3}$ cm2
Option 3: $150 \sqrt{3}$ cm2
Option 4: $350 \sqrt{3}$ cm2
Question : The perimeter of an equilateral triangle is 48 cm. Find its area (in cm2).
Option 1: $81\sqrt{3}$
Option 2: $8\sqrt{3}$
Option 3: $25\sqrt{3}$
Option 4: $64\sqrt{3}$
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