Question : In $\Delta ABC$, two points $D$ and $E$ are taken on the lines $AB$ and $BC,$ respectively in such a way that $AC$ is parallel to $DE$. Then $\Delta ABC$ and $\Delta DBE$ are:
Option 1: Similar only if $D$ lies outside the line segment $AB$.
Option 2: Congruent only if $D$ lies outside the line segment $AB$.
Option 3: Always similar.
Option 4: Always congruent.
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Correct Answer: Always similar.
Solution : We have, $D$ and $E$ are the points on $AB$ and $BC$. Such that $AC$ is parallel to $DE$. In $\Delta ABC$ and $\Delta DBE$, $\angle A=\angle D$ (Corresponding angle) $\angle C=\angle E$ (Corresponding angle) $\therefore \Delta ABC\sim\Delta DBE$ (by AA similarity) Hence, the correct answer is Always similar.
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Question : D and E are points on sides AB and AC of $\Delta ABC$. DE is parallel to BC. If AD : DB = 2 : 3. What is the ratio of the area of $\Delta ADE$ and the area of quadrilateral BDEC?
Option 1: 4 : 21
Option 2: 4 : 25
Option 3: 4 : 29
Option 4: 4 : 9
Question : In $\triangle ABC$ and $\triangle PQR, \angle B=\angle Q, \angle C=\angle R$ and $AB=2PQ$, then the two triangles are:
Option 1: congruent as well as similar
Option 2: neither similar nor congruent
Option 3: similar but not congruent
Option 4: congruent but not similar
Question : In $\triangle ABC$, $D$ and $E$ are the points of sides $AB$ and $BC$ respectively such that $DE \parallel AC$ and $AD : DB = 3 : 2$. The ratio of the area of trapezium $ACED$ to that of $\triangle DBE$ is:
Option 1: $4:15$
Option 2: $15:4$
Option 3: $4:21$
Option 4: $21:4$
Question : In $\Delta ABC$ the straight line parallel to the side $BC$ meets $AB$ and $AC$ at the point $P$ and $Q,$ respectively. If $AP=QC$, the length of $AB$ is $\operatorname{12 units}$ and the length of $AQ$ is $\operatorname{2 units}$, then the length (in units) of $CQ$ is:
Option 1: $4$
Option 2: $6$
Option 3: $8$
Option 4: $10$
Question : In $\triangle$ABC, D and E are two points on the sides AB and AC, respectively, so that DE $\parallel$ BC and $\frac{AD}{BD}=\frac{2}{3}$. Then $\frac{\text{Area of trapezium DECB}}{\text{Area of $\triangle$ABC}}$ is equal to:
Option 1: $\frac{5}{9}$
Option 2: $\frac{21}{25}$
Option 3: $1\frac{4}{5}$
Option 4: $5\frac{1}{4}$
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