Question : $\triangle PQR$ is right-angled at $Q$. The length of $PQ$ is 5 cm and $\angle P R Q=30^{\circ}$. Determine the length of the side $QR$.
Option 1: $5 \sqrt{3}~cm$
Option 2: $3 \sqrt{3}~cm$
Option 3: $\frac{1}{\sqrt{3}}~cm$
Option 4: $\frac{5}{\sqrt{3}}~cm$
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Correct Answer: $5 \sqrt{3}~cm$
Solution : $\angle PRQ$ = 30° ⇒ $\tan 30° = \frac{PQ}{QR}$ ⇒ $\frac{1}{\sqrt3} = \frac{5}{QR}$ ⇒ $QR = 5\sqrt{3}$ cm Hence, the correct answer is $5\sqrt{3}~cm$.
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Question : In $\triangle P Q R$, $\angle Q=90^{\circ}$, $PQ=8$ cm and $\angle P R Q=45^{\circ}$ Find the length of $QR$.
Option 1: 6 cm
Option 2: 3 cm
Option 3: 5 cm
Option 4: 8 cm
Question : It is given that ABC $\cong$ PQR, AB = 5 cm, $\angle$B = $40^{\circ}$, and $\angle$A = $80^{\circ}$. Which of the following options is true?
Option 1: PQ = 5 cm and $\angle$R = $60^{\circ}$
Option 2: QR = 5 cm and $\angle$R = $60^{\circ}$
Option 3: QR = 5 cm and $\angle$Q = $60^{\circ}$
Option 4: PQ = 5 cm and $\angle$P = $60^{\circ}$
Question : In a right-angled triangle $\Delta PQR, PR$ is the hypotenuse of length 20 cm, $\angle PRQ = 30^{\circ}$, the area of the triangle is:
Option 1: $50\sqrt{3}\text{ cm}^{2}$
Option 2: $100\sqrt{3}\text{ cm}^{2}$
Option 3: $25\sqrt{3}\text{ cm}^{2}$
Option 4: $\frac{100}{\sqrt{3}}\text{ cm}^{2}$
Question : PQR is a triangle right-angled at Q and PQ : QR = 3 : 4. What is the value of $\sin P + \sin Q + \sin R?$
Option 1: $\frac{4}{5}$
Option 2: $\frac{3}{5}$
Option 3: $\frac{12}{5}$
Option 4: $\frac{2}{5}$
Question : In a right-angled triangle PQR, right-angled at Q, the length of the side PR is 17 units, the length of the base QR is 8 units, and the length of the side PQ is 15 units. If $\angle RPQ = \sin\alpha $, then $\sin\alpha + \cos\alpha$ is:
Option 1: $\frac{18}{17}$
Option 2: $\frac{23}{17}$
Option 3: $\frac{21}{17}$
Option 4: $\frac{15}{17}$
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