It is given that, the density of an object placed on the surface of water is 10 kgm-3 and the density of water is 10-3 kgm-3. What will be the relative density of the object?

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It is given that, the density of an object placed on the surface of water is 10 kgm-3 and the density of water is 10-3 kgm-3. What will be the relative density of the object?

PRADEEP KUMAR 5th Nov, 2021

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PRADEEP KUMAR 5th Nov, 2021

Given :

Density of object = 10 kgm ^-3

Density of water = 10 ^-3 kgm ^-3

To find : Relative density of object

Formula for Relative density 🡪 Relative density =Density of object/Density of water

=10kgm ^-3 /10-3kgm ^-3

=0.01

Hence, relative density of object is 0.01

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