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It is given that, the density of an object placed on the surface of water is 10 kgm-3 and the density of water is 10-3 kgm-3. What will be the relative density of the object?


PRADEEP KUMAR 5th Nov, 2021
Answer (1)
PRADEEP KUMAR 5th Nov, 2021

Given : 


                            Density of object = 10 kgm-3


                            Density of water = 10-3 kgm-3


               To find :  Relative density of object


                 Formula for Relative density 🡪  Relative density =Density of object/Density of water


                                                                                                 =10kgm-3/10-3kgm-3


                                                                                                  =0.01   


                            Hence, relative density of object is 0.01    

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