Hello

I am guessing that you are asking about percentile.

Actually,

Your nta score in jee main result is nothing but your percentile dear.

For example,

If your nta score is 85 then your percentile is 85 percentile.

Admission is on the basis of rank, and your rank will be mentioned on your 4th session results ( your best percentile out of the all the 4 attempts / session is considered for giving you rank)

Your jee main 4th  session results will contain details like

-------)your nta score/percentile for all the 4 sessions .

- ------)   Your rank

-------) jee main qualifying cut off percentile

The date for the release of jee main 4th session result has not been announced yet but yes it will be tentatively released by 10th September 2021, for updates about the result ,you can follow our page at

https://engineering.careers360.com/articles/jee-main-result

You can check your result following the given below steps once it is out -

****** first of all visit the official page of jee main i. e jeemain.nta.nic.in  and then click on view Jee main result 2021.

******Now you need to login using your jee main application number & date of birth

******your result will get displayed on the screen

******Finally download your results and take a few copies of printout for future reference.

To predict your rank, you can use our rank predictor for which link is provided below :-

For previous year cut offs of top colleges like NITs, IIITs, GFTIs , you can refer our page at :-

https://engineering.careers360.com/articles/jee-main-cutoff

Or alternately you can visit official website of josaa at

https://josaa.nic.in/Result/Result/currentorcr.aspx

To have a personalised report on your chances of getting a college you can go through our college predictor, it will give you complete list of colleges which you can get on the basis of the category you belong to, your home state, your gender etc, the link for jee main college predictor is provided below

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

Thank you