25 Views
Question : Let $x$ be the least number of 4 digits that when divided by 2, 3, 4, 5, 6 and 7 leaves a remainder of 1 in each case. If $x$ lies between 2000 and 2500, then what is the sum of the digits of $x$?
Option 1: 4
Option 2: 15
Option 3: 9
Option 4: 10
Answer (1)
Correct Answer: 4
Solution :
LCM of 2, 3, 4, 5, 6 and 7 is 420.
The number should be between 2000 and 2500.
So, the number is = 420 × 5 = 2100
The remainder will be 1 in each case so the number = 2100 + 1 = 2101
Sum of digit of the number 2101 is = 2 + 1 + 0 + 1 = 4
Hence, the correct answer is 4.
Know More About
Related Questions
Upcoming Exams
Application Date:
2 Jun, 2025
- 23 Jun, 2025
Application Date:
2 Jun, 2025
- 30 Jun, 2025
1st Stage CBT
Exam Date:
5 Jun, 2025
- 24 Jun, 2025
Admit Card Date:
28 May, 2025
- 9 Jun, 2025
Admit Card Date:
9 Jun, 2025
- 30 Jun, 2025