Question : Meenu is 38 years old. Her daughter is 8 years old. In how many years will Meenu be double her daughter's age?
Option 1: 22
Option 2: 25
Option 3: 20
Option 4: 24
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Correct Answer: 22
Solution : Meenu's present age = 38 years Daughter's present age = 8 years Let be the after $x$ number of years from the present year for Meenu's age be twice of that of her daughter's age. $\therefore$ $38+x=2(8+x)$ ⇒ $38-16=x$ ⇒ $x=22$ years Hence, the correct answer is 22.
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Question : Direction: A mother is five times older than her daughter. After 5 years, she would be 3 times older than her daughter. Find the mother's present age.
Option 1: 20 years
Option 2: 22 years
Option 3: 25 years
Option 4: 29 years
Question : Direction: Joan's age is 42, and Kelvin's age is 26. How many years ago was Kelvin's age half of Joan's age?
Option 1: 6 years
Option 2: 4 years
Option 3: 10 years
Option 4: 8 years
Question : The ratio of A's age to B's age is $4:3$. A will be 26 years old after 6 years. The age of B now is:
Option 1: $19\frac{1}{2}$ years
Option 2: $12$ years
Option 3: $21$ years
Option 4: $15$ years
Question : Direction: Two years ago, Aadhya was three times as old as his son, and two years hence, twice her age will be equal to five times that of her son. Find Aadhya's present age.
Option 1: 38 years
Option 2: 36 years
Option 3: 34 years
Option 4: 42 years
Question : Direction: The average age of 19 boys in a class is 21 years. If the teacher's age is included, the average increases to 22 years. What is the teacher's age?
Option 1: 39 years
Option 2: 41 years
Option 3: 40 years
Option 4: 44 years
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