Hi Jai,

You got 93.74 percentile in JEE main 2 exam, your rank would be approximately in between 7000 to 8000.  Also, Above is the range of your possible rank. The predicted rank may vary due to JEE Main tie breaker rules for the same score. Also, you can check your expected rank using the formula:

Rank = (100-percentile)*(No. of students appeared for the examination)/100

As the no. of students appeared for Paper 2 are 112680, your rank will be around 7500. However as the no. of students in April changes, your rank will change according to that.On the basis of your percentile, you will get some colleges:

• Manipal university Aizwal
• Ansal university
• LPU Punjab
• Integral university Lucknow

Also to get NIT , you need to score the rank under 3000. If you have cleared JEE Advanced with a good score you have a chance to get IITs. The cutoff for Indian Institute of Technology Kharagpur  is in between 5783 -10310, and for Indian Institute of Technology Roorkee the cutoff goes from 4000- 10000.

You can also go through our college predictor to check which colleges you are eligible for through your JEE Mains score. The link for the college predictor is :