94 Views

n2 + 3 H2 receiver with 2 NH3 at 298 Kelvin given KP equals to 6.8 into 10 power 5


Bhupendra chandravanshi 19th Jan, 2020
Answer (1)
Mounika Sonti 29th May, 2020

Hello!!!!

Hope you are doing great!!!

If you want to find Kc, then the procedure is as follows:::;

As per the question reaction is as follows:

N2+3H2  gives rise to 2NH3

Kp=Kc*(RT)^Δ n

Δn= -2  (As per the given reaction)

Given Kp=6.8*10^5

R=8.314 atm.lit/mol.k

T=298 Kelvin

6.8*10^5 = Kc/(RT)^2

Kc=(6.8*10^5) x (RT)^ 2

Kc=(6.8*10^5) x (8.318 * 298 )^2

On Solving,We get Kc=4.5*10^12

Hope it helps!!!!



Related Questions

Amity University-Noida B.Tech...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Amity University-Noida MBA Ad...
Apply
Ranked among top 10 B-Schools in India by multiple publications | Top Recruiters-Google, MicKinsey, Amazon, BCG & many more.
Narayana Business School MBA/...
Apply
Top 30 Private B-Schools Nationally and Top 3 in Gujarat | Highest CTC- 20 LPA | Average CTC- 8.4 LPA | 40% Pre-Placement Offers | 670+ Recruiters 
Amity University | M.Tech Adm...
Apply
Asia’s only university to be awarded the highest accreditation by WASC, USA and by the Quality Assurance Agency for Higher Education (QAA), UK
JAGSoM PGDM Admissions 2026
Apply
Highest CTC 51.38 LPA | Median CTC 10.32 LPA | Top 25% Average CTC 14.32 LPA
IFMR Graduate School of Busin...
Apply
Application Deadline 15th Jan’26 | UGC Approved Programs | Near 100% Placement Record | Up to 100% Scholarships | Highest CTC 21.32 LPA
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books