Question : O is the centre of the circle and $\angle AOB = 150°$, and the shaded portion is $x$ part of the circular region, then what will be the value of $x$?
Option 1: $\frac{1}{12}$
Option 2: $\frac{1}{9}$
Option 3: $\frac{1}{6}$
Option 4: $\frac{1}{4}$
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Correct Answer: $\frac{1}{6}$
Solution :
Given: O is the centre of the circle and $\angle AOB = 150°$. We know that the vertically opposite angles are identical. ⇒ $\angle COD=150°$ Now, The angles between the shaded region and the two angles $\angle AOB$ and $\angle COD$ are making a complete circle. Let each shaded portion make an angle of $y°$ at the centre. ⇒ $150°+y°+150°+ y°=360°$ ⇒ $2y+300°=360°$ ⇒ $2y=60°$ ⇒ The shaded region covers 60° of the complete circle i.e., $x=\frac{60°}{360°}=\frac{1}{6}$ Hence, the correct answer is $\frac{1}{6}$.
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Question : AB is the diameter of a circle with centre O. If P is a point on the circle such that $\angle$AOP=110°, then the measure of $\angle$OBP is:
Option 1: 50°
Option 2: 65°
Option 3: 60°
Option 4: 55°
Question : In $\triangle A B C, O$ is the point of intersection of the bisectors of $\angle B$ and $\angle A$. If $\angle B O C=108^{\circ}$, then $\angle B A O=$?
Option 1: 27°
Option 2: 40°
Option 3: 18°
Option 4: 36°
Question : In the given figure, $O$ is the centre of the circle and $\angle AOC=140°$. Find $\angle ABC$.
Option 1: 95°
Option 2: 110°
Option 3: 120°
Option 4: 103°
Question : If RP and RQ are two tangents to a circle with centre O, such that $\angle POQ=120°$, where P and Q are the points on the circle and R is a point outside the circle, then $\angle PRQ$ is equal to:
Option 1: 90°
Option 2: 75°
Option 4: 45°
Question : Let P and Q be two points on a circle with centre O. If two tangents of the circle through P and Q meet at A with $\angle PAQ=48^{\circ}$, then $\angle APQ$ is:
Option 1: 96°
Option 2: 48°
Option 3: 66°
Option 4: 124°
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