Question : O is the incentre of the $\triangle \mathrm{PQR}$. If $\angle \mathrm{POR}=120°$, then what is the $\triangle \mathrm{PQR}$?
Option 1: 45°
Option 2: 60°
Option 3: 55°
Option 4: 48°
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Correct Answer: 60°
Solution : Given, $\angle POR = 120°$ We know, Angle at incentre = $90° + \frac{\text{vertex angle}}{2}$ ⇒ $90° + \frac{\angle PQR}{2} = 120°$ ⇒ $\frac{\angle PQR}{2} = 120° - 90°$ ⇒ $\frac{\angle PQR}{2} = 30°$ ⇒ $\angle PQR=60°$ Hence, the correct answer is 60°.
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Question : In $\triangle \mathrm{PQR}, \angle \mathrm{P}=46^{\circ}$ and $\angle \mathrm{R}=64^{\circ}$.If $\triangle \mathrm{PQR}$ is similar to $\triangle \mathrm{ABC}$ and in correspondence, then what is the value of $\angle \mathrm{B}$?
Option 1: 70°
Option 2: 90°
Option 3: 100°
Option 4: 110°
Question : I is the incentre of the $\triangle$XYZ. If $\angle$YIZ = 115°, then what is the $\angle$YXZ?
Option 1: 55°
Option 2: 45°
Option 3: 50°
Option 4: 60°
Question : M is the incentre of the $\triangle $XYZ. If $\angle $YXZ + $\angle $YMZ = 150°, then what is the value of $\angle $YXZ?
Option 1: 40°
Option 2: 55°
Option 3: 60°
Option 4: 45°
Question : In $\triangle \mathrm{STU}, \mathrm{SX}$ is the median on $\mathrm{TU}$. If $\mathrm{SX}=\mathrm{TX}$, then what is the value of $\angle \mathrm{TSU}$?
Option 1: 75°
Option 4: 90°
Question : If in $\triangle PQR$ and $\triangle DEF, \angle P=52^{\circ}, \angle Q=74^{\circ}, \angle R=54^{\circ}, \angle D=54^{\circ}, \angle E=74^{\circ}$ and $\angle F=52^{\circ}$, then which of the following is correct?
Option 1: $\triangle \mathrm{PQR} \sim \triangle \mathrm{FED}$
Option 2: $\triangle \mathrm{RQP} \sim \triangle \mathrm{FED}$
Option 3: $\triangle \mathrm{PRQ} \sim \Delta \mathrm{FED}$
Option 4: $\triangle \mathrm{PQR} \sim \triangle \mathrm{DEF}$
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