Question : PQR is an equilateral triangle inscribed in a circle. S is any point on the arc QR. Measure of $\frac{1}{2} \angle \mathrm{PSQ}$ is:
Option 1: 20°
Option 2: 15°
Option 3: 30°
Option 4: 60°
Correct Answer: 30°
Solution :
Since PQR is an equilateral triangle inscribed in a circle, each of its angles is 60°. $\angle PSQ=\angle QRP = $ 60° (Angles in the same segment) $\frac{1}{2}\times \angle PSQ=\frac{60°}{2}=30°$ Hence, the correct answer is 30°.
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Question : In a triangle$\frac{AB}{AC}=\frac{BD}{DC}$, $\angle$B = 70° and $\angle$C = 50°, then $\angle$BAD =?
Option 1: 60°
Option 2: 20°
Option 4: 50°
Question : $\triangle \mathrm{ABC}$ and $\triangle \mathrm{DEF}$ are two triangles such that $\triangle \mathrm{ABC} \cong \triangle \mathrm{FDE}$. If AB = 5 cm, $\angle$B = 40° and $\angle$A = 80°, then which of the following options is true?
Option 1: DF = 5 cm, $\angle$E = 60°
Option 2: DE = 5 cm, $\angle$F = 60°
Option 3: DE = 5 cm, $\angle$D = 60°
Option 4: DE = 5 cm, $\angle$E = 60°
Question : In $\triangle \mathrm{ABC}, \angle \mathrm{A}=68^{\circ}$. If I is the incentre of the triangle, then the measure of $\angle B I C$ is:
Option 1: 124°
Option 2: 68°
Option 3: 148°
Option 4: 54°
Question : In a $\triangle \mathrm{PQR}$ and $\triangle\mathrm{ABC}$, $\angle$P = $\angle$A and AC = PR. Which of the following conditions is true for $\triangle$PQR and $\triangle$ABC to be congruent?
Option 1: AB = PQ by SSS
Option 2: AB = PQ by SAS
Option 3: BC = QR by ASS
Option 4: $\angle$Q = $\angle$B by AAA
Question : In $\triangle A B C, \mathrm{BD} \perp \mathrm{AC}$ at $\mathrm{D}$. $\mathrm{E}$ is a point on $\mathrm{BC}$ such that $\angle B E A=x^{\circ}$. If $\angle E A C=46^{\circ}$ and $\angle E B D=60^{\circ}$, then the value of $x$ is:
Option 1: 72°
Option 2: 78°
Option 3: 68°
Option 4: 76°
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