Question : Simplify: $\sqrt{\frac{4\frac{1}{7}-2\frac{1}{4}}{3\frac{1}{2}+1\frac{1}{7}}+\frac{2}{2+\frac{1}{2+\frac{1}{5-\frac{1}{5}}}}}$
Option 1: $1$
Option 2: $4$
Option 3: $\sqrt{\frac{159}{130}}$
Option 4: $2$
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Correct Answer: $\sqrt{\frac{159}{130}}$
Solution : $\sqrt{\frac{4\frac{1}{7}-2\frac{1}{4}}{3\frac{1}{2}+1\frac{1}{7}}+\frac{2}{2+\frac{1}{2+\frac{1}{5-\frac{1}{5}}}}}$ = $\sqrt{\frac{\frac{29}{7}-\frac{9}{4}}{\frac{7}{2}+\frac{8}{7}}+\frac{2}{2+\frac{1}{2+\frac{5}{24}}}}$ = $\sqrt{\frac{\frac{53}{28}}{\frac{65}{14}}+\frac{2}{2+\frac{24}{53}}}$ = $\sqrt{\frac{53}{130}+\frac{106}{130}}$ = $\sqrt{\frac{159}{130}}$ Hence, the correct answer is $\sqrt{\frac{159}{130}}$.
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Question : If $x=5–\sqrt{21}$, the value of $\frac{\sqrt{x}}{\sqrt{32–2x}–\sqrt{21}}$ is:
Option 1: $\frac{1}{\sqrt2}(\sqrt{3}–\sqrt{7})$
Option 2: $\frac{1}{\sqrt2}(\sqrt{7}–\sqrt{3})$
Option 3: $\frac{1}{\sqrt2}(\sqrt{7}+\sqrt{3})$
Option 4: $\frac{1}{\sqrt2}(7–\sqrt{3})$
Question : If $a^2+\frac{1}{a^2}=\frac{7}{3}$, then what is the value of $\left(a^3-\frac{1}{a^3}\right)?$
Option 1: $\frac{5}{3 \sqrt{3}}$
Option 2: $\frac{10}{3 \sqrt{3}}$
Option 3: $\frac{7}{3 \sqrt{3}}$
Option 4: $\frac{8}{3 \sqrt{3}}$
Question : If $x=(7+3 \sqrt{5})$, then find the value of $x^2+\frac{1}{x^2}$.
Option 1: $ \frac{580+315 \sqrt{5}}{8}$
Option 2: $\frac{799+328 \sqrt{5}}{8}$
Option 3: $\frac{799+315 \sqrt{5}}{12}$
Option 4: $\frac{799+315 \sqrt{5}}{8}$
Question : If $\sin \theta = \frac{3}{11}$, then what is the value of $\cot \theta$?
Option 1: $\frac{3 \sqrt{7}}{11}$
Option 2: $\frac{4 \sqrt{7}}{11}$
Option 3: $\frac{4 \sqrt{7}}{3}$
Option 4: $\frac{3 \sqrt{7}}{28}$
Question : If $x=(\sqrt{6}-1)^{\frac{1}{3}}$, then the value of $\left(x-\frac{1}{x}\right)^3+3\left(x-\frac{1}{x}\right)$ is:
Option 1: $\frac{2 \sqrt{6}-6}{5}$
Option 2: $\frac{4 \sqrt{6}-6}{5}$
Option 3: $\frac{4 \sqrt{6}-6}{3}$
Option 4: $\frac{4 \sqrt{3}-6}{5}$
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