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Sir i got 94.35 percentile in jee mains paper 1 ..i am from obc category and my home state is patna(bihar) which nit i get ?


Rahul Raj 24th Feb, 2019
Answers (3)
UTKARSH DUBEY 24th Feb, 2019
Hello Rahul,
You can get government college with this percentile.
According to our expert 85 percentile marks are required to clear Jee main for general candidate.
OBC candidate have 5-7 percentile exemption.
As you get above 94 percentile you have chances to get core branches in good NITs. With help of home state quota you can easily get home state NIT.
This percentile going to varies in April Jee main.
To understand percentile system follow the link below:https://engineering.careers360.com/articles/jee-main-normalisation-process-how-scores-are-calculated
Note:careers360 is not responsible for any varies in prediction. Prediction is based on previous year cutoffs. NTA results is final
If you have any questions remain than comment below.
Good luck...

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1 Comment
Comments (1)
6th Feb, 2020
To get CS in NIT Durgapur what is the cut off marks for SC candidates.
Reply
Anuj Goyal 24th Feb, 2019

Hello Rahul,

As per your percentile your OBC rank will be around 15,000. You'll surely land in an NIT with this score apart from this you are from OBC category. Considering last year cutoff you'll easily get IT, ETC or Mechanical in average NIT's if there is special round. You can even go gor 5 year integrated M.Sc course in NIT Patna as last year closing rank in some of its branch was 15,000 but be you need to compensate with your branch too. So choose your branch wisely then choose your college because sometimes one needs to compensate.

Hope this helps. For further queries you can ask.

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narendersingh3163_8250305 Student Expert 24th Feb, 2019

Hey dear, according to your percentile in jee mains your obc rank will be approx 15k you can get following colleges like NIT Durgapur, nit jamshedpur ,NIT ROURKELA,NIT PATNA,  etc BUT you may have to compensate with branch. 

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