Question : Some carpenters promised to complete the work in 20 days. When the work was started, 8 of them were absent and the remaining completed the work in 40 days. What was the original number of carpenters?
Option 1: 18
Option 2: 12
Option 3: 10
Option 4: 16
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Correct Answer: 16
Solution : Number of days promised, $D_1$ = 20 days Number of days taken to complete the work, $D_2$ = 40 Let the number of carpenters($M_1$) be $x$ Absent carpenters = 8 Remaining carpenters($M_2$) = $(x-8)$ We know that, $M_1D_1= M_2D_2$ ⇒ $x\times20=(x-8)\times40$ ⇒ $20x=40x-320$ ⇒ $20x=320$ ⇒ $x=16$ Hence, the correct answer is 16.
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Question : A can complete 25% of a work in 10 days. B can complete 40% of the same work in 16 days. In how many days will A and B together complete twice the work mentioned above?
Option 1: 20
Option 2: 40
Option 3: 60
Option 4: 50
Question : A work can be completed by 20 men in 50 days. 30 more men join them after 10 days of work. How many days will be saved in the completion of the work?
Option 1: 18 days
Option 2: 20 days
Option 3: 24 days
Option 4: 28 days
Question : B and C can complete work alone in 10 days and 30 days respectively. They began the work together but B left the work after some days and C completed the remaining work in 10 days. After how many days from the beginning B left the work?
Option 1: 4 days
Option 2: 6 days
Option 3: 8 days
Option 4: 5 days
Question : A work can be completed by N men in 15 days. 5 men leave the work after 3 days. The remaining work was completed in 18 days. What is the value of N?
Option 2: 21
Option 3: 15
Option 4: 12
Question : A, B, and C can complete a work in 10, 12, and 15 days respectively. They started the work together, but A left the work before five days of its completion. B also left the job two days after A left. In how many days was the work completed?
Option 2: 5 days
Option 3: 7 days
Option 4: 8 days
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