Question : Some staff promised to do a job in 18 days, but 6 of them went on leave. So the remaining men took 20 days to complete the job. How many men were there originally?
Option 1: 55
Option 2: 62
Option 3: 56
Option 4: 60
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Correct Answer: 60
Solution : Let the total number of men be $x$. The work is the same. So, $W_1=W_2=1$ Use the following formula to solve the question: $\frac{M_{1}\times D_{1}}{W_{1}}=\frac{M_{2}\times D_{2}}{W_{2}}$ Where $M_1$ and $M_2$ are men, $D_1$ and $D_2$ are days and $W_1$ and $W_2$ are work done. $\frac{x×18}{1}=\frac{(x-6)20}{1}$ $⇒ 18x= 20x-120$ $⇒ 2x = 120$ $\therefore x= 60$ Hence, the correct answer is 60.
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Question : 40 men can complete a work in 18 days. Eight days after they started working together, 10 more men joined them. How many days will it now take to complete the remaining work?
Option 1: 6
Option 2: 8
Option 3: 10
Option 4: 12
Question : Three men can complete a piece of work in 6 days. Two days after they started the work, 3 more men joined them. How many days will it take to complete the remaining work?
Option 1: 1 day
Option 2: 2 days
Option 3: 3 days
Option 4: 4 days
Question : 16 women take 12 days to complete a work which can be completed by 12 men in 8 days. 16 men started working and after 3 days 10 men left and 4 women joined them. How many days will it take them to complete the remaining work?
Option 1: 4
Option 2: 6
Option 3: 8
Option 4: 10
Question : How many men need to be employed to complete a job in 5 days, if 15 men can complete $\frac{1}{3}$ of the job in 7 days?
Option 1: 20
Option 2: 21
Option 3: 45
Option 4: 63
Question : 8 men or 10 boys can complete a work in 174 days. 12 men and 14 boys will complete the same work in how many days?
Option 1: 60 days
Option 2: 50 days
Option 3: 72 days
Option 4: 84 days
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