Correct Answer: D

Solution : Number of students who appeared in the examination from institutes B = 54^\circ 
= $\frac{54^\circ}{360^\circ} × 1200$ 
= 180
Number of students who appeared in the examination from institutes C = 90^\circ 
= $\frac{90^\circ}{360^\circ} × 1200$ 
= 300
Number of students who appeared in the examination from institutes D = 105^\circ
= $\frac{105^\circ}{360^\circ} × 1200$ 
= 350
Number of students who appeared in the examination from institutes E = 39^\circ
= $\frac{39^\circ}{360^\circ} × 1200$ 
= 130
Number of students who passed the examination from institutes B = 18%
= $900 \times \frac{18}{100}$
= 162
Number of students who passed the examination from institutes C = 30%
= $900 \times \frac{30}{100}$
= 270
Number of students who passed the examination from institutes D = 28%
= $900 \times \frac{28}{100}$
= 252
Numbers of students who passed the examination from institutes E = 9%
= $900 \times \frac{9}{100}$
= 81
The percentage of students of institute B passed to the students who appeared from that institute = $\frac{162}{180} \times 100$
= 90%
The percentage of students of institute C passed to the students who appeared from that institute = $\frac{270}{300} \times 100$
= 90%
The percentage of students of institute D passed to the students who appeared from that institute = $\frac{252}{350} \times 100$
= 72%
The percentage of students of institutes E passed to the students who appeared from that institute = $\frac{81}{130} \times 100$
= 62.30%
So, the second highest percentage of students who passed to the students who appeared is from institute D = 72%
Hence the correct answer is D.