Question : Suppose that the medians BD, CE, and AF of a triangle ABC meet at G. Then AG : GF is:
Option 1: 1 : 2
Option 2: 2 : 1
Option 3: 1 : 3
Option 4: 2 : 3
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Correct Answer: 2 : 1
Solution : Here, G is the centroid of the $\triangle$ABC. The Centroid of the triangle divides each median into a 2 : 1 ratio. Hence, the correct answer is 2 : 1.
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Question : If ABC is an equilateral triangle and D is a point in BC such that AD is perpendicular to BC, then:
Option 1: AB : BD = 1 : 1
Option 2: AB : BD = 1 : 2
Option 3: AB : BD = 2 : 1
Option 4: AB : BD = 3 : 2
Question : Three medians AD, BE, and CF of $\triangle ABC$ intersect at G. The area of $\triangle ABC$ is $36\text{ cm}^2$. Then the area of $\triangle CGE$ is:
Option 1: $12\text{ cm}^2$
Option 2: $6\text{ cm}^2$
Option 3: $9\text{ cm}^2$
Option 4: $18\text{ cm}^2$
Question : G and AD are respectively the centroid and median of the triangle $\triangle$ABC. The ratio AG : AD is equal to:
Option 1: 3 : 2
Option 2: 2 : 3
Option 3: 2 : 1
Option 4: 1 : 2
Question : In $\triangle$ABC, the bisector of $\angle$BAC intersects BC at D and the circumcircle of $\triangle$ABC at E. If AB : AD = 3 : 5, then AE : AC is:
Option 1: 5 : 3
Option 2: 3 : 2
Option 3: 2 : 3
Option 4: 3 : 5
Question : G is the centroid of $\triangle$ABC. If AG = BC, then measure of $\angle$BGC is:
Option 1: 45°
Option 2: 60°
Option 3: 90°
Option 4: 120°
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