Question : The angle of elevation of the top of a building at a distance of 70 m from its foot on a horizontal plane is found to be 60°. Find the height of the building.
Option 1: $70 \sqrt{3} \mathrm{~m}$
Option 2: $60 \sqrt{3} \mathrm{~m}$
Option 3: $50 \sqrt{3} \mathrm{~m}$
Option 4: $70 \sqrt{2} \mathrm{~m}$
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Correct Answer: $70 \sqrt{3} \mathrm{~m}$
Solution : Height = AC We know, $\tan \theta=\frac{\text{Perpendicular}}{\text{Base}}$ ⇒ $\tan60° =\frac{AC}{70}$ ⇒ $\sqrt3=\frac{AC}{70}$ ⇒ $AC=70\sqrt3\text{ m}$ Hence, the correct answer is $70\sqrt3\text{ m}$.
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Question : The angle of elevation of the top of the pillar from the foot and the top of a building 20 m high, are 60° and 30°, respectively. The height of the pillar is:
Option 1: $10$ m
Option 2: $10\sqrt{3}$ m
Option 3: $60$ m
Option 4: $30$ m
Question : At 129 m away from the foot of a cliff on level ground, the angle of elevation of the top of the cliff is 30°. The height of this cliff is:
Option 1: $50\sqrt{3}$ m
Option 2: $45\sqrt{3}$ m
Option 3: $43\sqrt{3}$ m
Option 4: $47\sqrt{3}$ m
Question : From 40 metres away from the foot of a tower, the angle of elevation of the top of the tower is 60°. What is the height of the tower?
Option 1: $\frac{120}{\sqrt{3}}$ m
Option 2: $\frac{60}{{\sqrt3}}$ m
Option 3: $\frac{50}{{\sqrt3}}$ m
Option 4: $\frac{130}{{\sqrt7}}$ m
Question : The respective ratio between the height of the tower and the point at some distance from its foot is $5\sqrt{3}:5$. What will be the angle of elevation of the top of the tower?
Option 1: 30°
Option 2: 60°
Option 3: 90°
Option 4: 45°
Question : From the top of a 20 metres high building, the angle of elevation from the top of a tower is 60° and the angle of depression of its foot is at 45°, then the height of the tower is: $(\sqrt{3} = 1.732)$
Option 1: 45.46 metres
Option 2: 45.64 metres
Option 3: 54.64 metres
Option 4: 54.46 metres
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