180 Views

the angular velocity and amplitude of a simple pendulum is omega and A respectively at a displacement x if its KE is T and potential energy isU then the ratio of T to U is


Jayasree Patil 13th Apr, 2020
Answer (1)
KUNAL LANJEWAR 13th Apr, 2020

Hello,

We know that, for Simple Pendulum,

Kinetic Energy = T = [ m.ω^2 ( A^2 − x^2 ) ] / 2

Potential Energy = U = m.ω^2.x^2

Hence, Ratio of Kinetic Energy to the Potential Energy is,

T / U = ( A^2 - x^2 ) / x^2

i.e., T : U = ( A^2 - x^2 ) : x^2

Best Wishes.

Related Questions

Amity University-Noida B.Tech...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Amity University-Noida M.Tech...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Amity University-Noida BBA Ad...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
VIT Bhopal University | B.Arc...
Apply
Mark presence in the Modern Architectural field with Bachelor of Architecture | Highest CTC : 70 LPA | Accepts NATA Score
New Horizon College BBA Admis...
Apply
UG Admissions 2026 open| NAAC ‘A’ grade | Merit-based Scholarships available.
VIT Bhopal University | Integ...
Apply
Integrated M.Tech admissions open @ VIT Bhopal University | Highest CTC 70 LPA | Application Closing Soon | Apply now
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books